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belka [17]
4 years ago
5

Look PLZ,PLZ,PLZ help with this. I have no idea how to do this

Mathematics
1 answer:
scoray [572]4 years ago
8 0

Answer:

i know that number 4 is interceding lines because they are crossing each other

Step-by-step explanation:

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Before a computer is assembled, its motherboard goes through a special inspection. Assume only 85% of motherboards pass this ins
andreyandreev [35.5K]

Answer:

(a) The probability that at least 13 of the next 15 motherboards pass inspection is 0.6042.

(b) On average, 1.18 motherboards should be inspected until a motherboard that passes inspection is found.

Step-by-step explanation:

Let <em>X</em> = number of motherboards that pass the inspection.

The probability that a motherboards pass the inspection is P (X) = <em>p</em> = 0.85.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.

The probability mass function of <em>X</em> is,

P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,3...

(a)

Compute the probability that at least 13 of the next 15 motherboards pass inspection as follows:

P (X ≥ 13) = P (X=  13) + P (X = 14) + P (x = 15)

               ={15\choose 13}0.85^{13}(1-0.85)^{15-13}+{15\choose 13}0.85^{14}(1-0.85)^{15-14}\\+{15\choose 13}0.85^{16}(1-0.85)^{15-15}\\=0.2856+0.2312+0.0874\\=0.6042

Thus, the probability that at least 13 of the next 15 motherboards pass inspection is 0.6042.

(b)

Computed the expected number of motherboards should be inspected until a motherboard that passes inspection is found as follows:

Expected\ value=\frac{1}{p}=\frac{1}{0.85}= 1.1764\approx1.18

Thus, on average, 1.18 motherboards should be inspected until a motherboard that passes inspection is found.

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