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Vesna [10]
3 years ago
14

Math homework !! pls help , it’s due in 10 min :(( question 1: a , b , c, d

Mathematics
2 answers:
11111nata11111 [884]3 years ago
7 0
i think the answer is (A)
pishuonlain [190]3 years ago
5 0
The answer is B. due to the fact that, that’s were the goat started
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After, thorough research I believe that there are 265 pine trees and 0 elm trees since decidous and semi-decidous do not grow near conifers.

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3 years ago
State the hypotenuse, opposite and
UkoKoshka [18]

Answer:

hypotenuse:2 (AB)

adjacent side: 1 (AD)

opposite side:√3(BD)

Step-by-step explanation:

-->AB is hypotenuse cuz it's opposite to right angle (90°)

-->AD is adjacent,cuz it's adjacent to reference angle(60°)

-->BD is opposite side,cuz it's opposite to the reference angle(60°)

✌️:)

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3 years ago
I need help please help me answer this it’s due in like 15 minutes
Svetach [21]

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3 years ago
7. Find the width of the rectangular prism when the
ludmilkaskok [199]
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6 0
3 years ago
F(x)
mina [271]

a) Since both limits are <em>distinct</em> and do not exist, we conclude that x = - 1 is not part of the domain of the <em>rational</em> function.

b) The function f(x) = \frac{x}{x^{2}+ x} is equivalent to the function g(x) = \frac{1}{x + 1}.

<h3>How to determine whether a limit exists or not</h3>

According to theory of limits, a function f(x) exists for x = a if and only if \lim_{x\to a^{-}} f(x) = \lim_{x \to a^{+}} f(x). This criterion is commonly used to prove continuity of functions.

<em>Rational</em> functions are not continuous for all value of x, as there are x-values that make denominator equal to 0. Based on the figure given below, we have the following <em>lateral</em> limits:

\lim_{x \to -1^{-}} \frac{x}{x^{2}+x} = - \infty

\lim_{x \to -1^{+}} \frac{x}{x^{2}+x} = + \infty

Since both limits are <em>distinct</em> and do not exist, we conclude that x = - 1 is not part of the domain of the <em>rational</em> function.

In addition, we can simplify the function by <em>algebra</em> properties:

\frac{x}{x^{2}+ x} = \frac{x}{x\cdot (x + 1)} = \frac{1}{x + 1}

g(x) = \frac{1}{x + 1}

The function f(x) = \frac{x}{x^{2}+ x} is equivalent to the function g(x) = \frac{1}{x + 1}.

To learn more on lateral limits: brainly.com/question/21783151

#SPJ1

7 0
2 years ago
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