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Brilliant_brown [7]

3 years ago

12

What is the difference between plotting (2, 3) and (3,2) on a coordinate plane? Explain

2 answers:

ollegr [7]3 years ago

8 0

Answer:

When plotting coordinates, the first number is called your X axis, while the second number is your Y. Since the X axis goes left and right, and the Y axis goes up and down, plotting (2,3) would be a point closer to the bottom of the graph and somewhere in the right. (3,2) would be higher up and less far right.
Hope this helps and by plotting them, you could visualize these concepts more.
Happy studying!

Lunna [17]3 years ago

5 0

Answer:

Step-by-step explanation:

2,3 has I lower unit than 3,2 let’s say that we plot it we see that 2,3 is lower down 3,2 :)

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Find the solution of the differential equation that satisfies the given initial condition. y' tan x = 3a + y, y(π/3) = 3a, 0 &lt

Paladinen [302]

Answer:

$y(x)=4a\sqrt{3}* sin(x)-3a$

Step-by-step explanation:

We have a separable equation, first let's rewrite the equation as:

$\frac{dy(x)}{dx} =\frac{3a+y}{tan(x)}$

But:

$\frac{1}{tan(x)} =cot(x)$

So:

$\frac{dy(x)}{dx} =cot(x)*(3a+y)$

Multiplying both sides by dx and dividing both sides by 3a+y:

$\frac{dy}{3a+y} =cot(x)dx$

Integrating both sides:

$\int\ \frac{dy}{3a+y} =\int\cot(x) \, dx$

Evaluating the integrals:

$log(3a+y)=log(sin(x))+C_1$

Where C1 is an arbitrary constant.

Solving for y:

$y(x)=-3a+e^{C_1} sin(x)$

$e^{C_1} =constant$

So:

$y(x)=C_1*sin(x)-3a$

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$y(\frac{\pi}{3} )=3a=C_1*sin(\frac{\pi}{3})-3a\\ 3a=C_1*\frac{\sqrt{3} }{2} -3a$

Solving for C1:

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Therefore:

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3 years ago