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postnew [5]
3 years ago
9

Please help me please

Mathematics
1 answer:
lisov135 [29]3 years ago
7 0

Answer:

3π ~ 9.42 cm^2

Step-by-step explanation:

S = πR^2h

S = π×1^2×3

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A Clydesdale drinks about 120 gallons of water every four days at this rate about how many gallons of water does
djyliett [7]

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480 gallons

Step-by-step explanation:


8 0
3 years ago
What is more precise 54.1cm or 54.16cm?????
prisoha [69]
I think 54.16 because 54.16 is greater than 54.1

3 0
3 years ago
Read 2 more answers
Simplify 6-(-14)+(-2)​
garik1379 [7]

Answer:

18

Step-by-step explanation:

when there is a - in front of an expression in parentheses, change the sign of each term in the expression

6+14+(-2)

then calculate the sum or difference

6+14-2= 18

3 0
3 years ago
The graph shows the amount of money Miguel earns
Novay_Z [31]

Answer:

Step-by-step explanation:

the function shows a comparison between 2 objects that change  

If we use function notation, the Average Rate of Change of a function from a to b can be formulated as:  

ROC = rate of change  

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the rate of change (ROC) :

done...

6 0
3 years ago
Read 2 more answers
Suppose 462 of 500 randomly selected college students said they would be embarrassed to truthfully admit they could not read at
ANEK [815]

Answer:

We conclude that there is a significant difference in the proportion of all college students who would be embarrassed by these two admissions.

Step-by-step explanation:

We are given that 462 of 500 randomly selected college students said they would be embarrassed to truthfully admit they could not read at a fourth grade level.

Further suppose 135 of 500 randomly selected college students said they would be embarrassed to truthfully admit they could not "do math" at a fourth grade level (like fractions).

<em>Let </em>p_1<em> = proportion of college students who would be embarrassed to truthfully admit they could not read at a fourth grade level.</em>

p_2<em> = proportion of college students who would be embarrassed to truthfully admit they could not "do math" at a fourth grade level.</em>

So, Null Hypothesis, H_0 : p_1-p_2 = 0  or  p_1= p_2     {means that there is not any significant difference in the proportion of all college students who would be embarrassed by these two admissions}

Alternate Hypothesis, H_A : p_1-p_2 \neq 0  or  p_1\neq p_2     {means that there is a significant difference in the proportion of all college students who would be embarrassed by these two admissions}

The test statistics that would be used here <u>Two-sample z proportion</u> <u>statistics</u>;

                       T.S. =  \frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2}  } }  ~ N(0,1)

where, \hat p_1 = sample proportion of college students who would be embarrassed to admit they could not read at a fourth grade level = \frac{462}{500} = 0.924

\hat p_2 = sample proportion of college students who would be embarrassed to admit they could not "do math" at a fourth grade level = \frac{135}{500} = 0.27

n_1 = sample of college students = 500

n_2 = sample of college students = 500

So, <em><u>test statistics</u></em>  =  \frac{(0.924-0.27)-(0)}{\sqrt{\frac{0.924(1-0.924)}{500}+\frac{0.27(1-0.27)}{500}  } }

                              =  28.28

The value of z test statistics is 28.28.

<u>Also, P-value of the test statistics is given by;</u>

          P-value = P(Z > 28.28) = Less than 0.0005%

<u></u>

<u>Now, at 0.10 significance level the z table gives critical values of -1.645 and 1.645 for two-tailed test.</u>

Since our test statistics doesn't lie within the range of critical values of z, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u>we reject our null hypothesis</u>.

Therefore, we conclude that there is a significant difference in the proportion of all college students who would be embarrassed by these two admissions.

5 0
4 years ago
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