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3 years ago

HELPEOEOOEOE HELP OELASDJ PLEASE

Mathematics

1 answer:

aleksandr82 [10.1K]3 years ago

5 0

Answer:

A then B

Step-by-step explanation:

1440≈1,000, and 1,000=10^3

1000000/1440≈700, and 700≈1,000. 1,000=10^3

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For a party, you buy 4 3/8 lbs of salt water taffy. If 150 people are attending, how much salt water taffy does each person get?

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Answer:

Step-by-step explanation

150 divided by 4 3/8 = 34.2

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3 years ago

A 10-ounce container of chocolate chips can be used to make 3 desserts. Each dessert has the same amount of chocolate chips. Whi

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4 years ago

Read 2 more answers

A doctor is interested in people who have experienced an unexplained episode of vitamin D intoxication. She took a SRS of size 1

Mila [183]

Answer:

(a) (2.573, 3.167) is the 99% confidence interval for $\mu$ the true mean calcium level of the population of people who experienced an unexplained episode of vitamin D intoxication.

(b) There is a 99% probability that the average calcium level of all people who have experienced an unexplained episode of vitamin D intoxication is in the interval.

Step-by-step explanation:

If we have a random sample of size n from a normal distribution with mean $\mu$ and standard deviation $\sigma$ , then we know that $\bar{X}$ is normally distributed with mean $\mu$ and standard deviation $\sigma/n$ . Therefore we can use $(\bar{X}-\mu)/\frac{\sigma}{\sqrt{n}}$ as a pivotal quantity.

We have a sample size of n = 12. The sample mean is $\bar{x}$ = 2.87 mmol/l and the standard deviation is $\sigma = 0.40$ . The confidence interval is given by $\bar{x}\pm z_{\alpha/2}(\frac{\sigma}{\sqrt{n}})$ where $z_{\alpha/2}$ is the $\alpha/2$ th quantile of the standard normal distribution. As we want the 99% confidence interval, we have that $\alpha = 0.01$ and the confidence interval is $2.87\pm z_{0.005}(\frac{0.40}{\sqrt{12}})$ where $z_{0.005}$ is the 0.5th quantile of the standard normal distribution, i.e., $z_{0.005} = -2.5758$ . Then, we have $2.87\pm (-2.5758)(\frac{0.40}{\sqrt{12}})$ and the 99% confidence interval is given by (2.573, 3.167)

(b) We found a 99% confidence interval for the true mean calcium level of the population of people who experienced an unexplained episode of vitamin D intoxication. Therefore, there is a 99% probability that the average calcium level of all people who have experienced an unexplained episode of vitamin D intoxication is in the interval.

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4 years ago

What is the square root of 45600 in fraction

Archy [21]

Answer:

The square root of 45600 is 20 $\sqrt{114}$