Answer:
for the first 2 neither one is a polygon because a polygon has straight sides and is closed connections were the first shape has an open connection and the second shape has a curved line. for question i believe is 48 and question 4 is 145.
explanation.
for the last 2 problems their total equal 360 so you just add up all the side then subtract the number you got by 360 and that's your answer. ex.) 120 +130+ 62=312. 360-312=48
Answer:
θ = π<em>n</em>
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Step-by-step explanation:
The answers to the questions
9514 1404 393
Answer:
∠CAB = 28°
∠DAC = 64°
Step-by-step explanation:
What you do in each case is make use of the relationships you know about angles in a triangle and around parallel lines. You can also use the relationships you know about diagonals in a rectangle, and the triangles they create.
<u>Left</u>
Take advantage of the fact that ∆AEB is isosceles, so the angles at A and B in that triangle are the same. If we call that angle measure x, then we have the sum of angles in that triangle is ...
x + x + ∠AEB = 180°
2x = 180° -124° = 56°
x = 28°
The measure of angle CAB is 28°.
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<u>Right</u>
Sides AD and BC are parallel, so diagonal AC can be considered a transversal. The two angles we're concerned with are alternate interior angles, so are congruent.
∠BCA = ∠DAC = 64°
The measure of angle DAC is 64°.
(Another way to look at this is that triangles BCE and DAE are congruent isosceles triangles, so corresponding angles are congruent.)
The area of this figure is 10
