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3 years ago

Find domain and range of the following function

Mathematics

1 answer:

Sergeu [11.5K]3 years ago

3 0

Answer:

Domain and Range are both all real numbers.

Step-by-step explanation:

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4x+1=5<br> Just a test have fun with free points!

ss7ja [257]

Answer:

x = 0.666(Repeating)

Step-by-step explanation:

4x+1=5

Subtract 1 from both sides

4x=6

Divide both sides by 4

x = 0.666(Repeating)

7 0

3 years ago

Read 2 more answers

I need help<br> please and thank you

REY [17]

I believe it’s
D.51is it B ??

7 0

3 years ago

I have 4 papers sizes 8.5 inches by 11 inches how many square feet are the 4 papers?

Mariulka [41]

Total area = 4 × 8.5 × 11 = 374 in²

374 in² = 374/144 = 2.597 ft²

7 0

3 years ago

Find the solution set of the following quadratic equations using the quadratic formula.

oksian1 [2.3K]

Answer:

<h3> 1) $x_1=\dfrac{7+\sqrt{13}}2\,,\quad x_2=\dfrac{7-\sqrt{13}}2$ </h3><h3> 2) $x_1=-\dfrac13\,,\quad x_2=-3$ </h3>

Step-by-step explanation:

$x^2 - 7x + 9 = 0\quad\implies\quad a=1\,,\ b = -7\,,\ c=9\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}=\dfrac{-(-7)\pm\sqrt{(-7)^2-4\cdot1\cdot9}}{2\cdot1}=\dfrac{7\pm\sqrt{49-36}}2\\\\x_1=\dfrac{7+\sqrt{13}}2\,,\quad x_2=\dfrac{7-\sqrt{13}}2$

<h3>2)</h3><h3> $3x^2 + 10x=-3\\\\3x^2+10x+3=0\quad\implies\quad a=3\,,\ b =10\,,\ c=3\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}=\dfrac{-10\pm\sqrt{10^2-4\cdot3\cdot3}}{2\cdot3}= \dfrac{-10\pm\sqrt{100-36}}6\\\\x_1=\dfrac{-10+\sqrt{64}}6=\dfrac{-10+8}6=-\dfrac13\,,\qquad x_2=\dfrac{-10-8}6=-3$ </h3>

7 0

3 years ago

Indicate the data relationship for each table. If each is, directly proportional or non-proportional

Alla [95]

It’s nonporportiniol sorry if it’s spelled wrong lol

5 0

3 years ago