The value of x is 77 cm which will make the triangles similar by SSS similarity theorem
Given length of the three sides of one triangle are 35 , 20 and 20
and length of the three sides of another triangle are x, 44,44
We need to find the values of x by using SSS Similarity theorem
We know that triangles are are similar by side - side - side similarity creation and hence the sides are in the same ratio
As both the triangles are isosceles triangles
Therefore ,
x/35 = 44/20=44/20 (Using ratio)
Solving the equation we get
x=44*35/20
x= 77
Hence the value of x is 77cm
Learn more about similarity of triangles here brainly.com/question/14285697
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Answer:
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Step-by-step explanation:
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That is your correct answer
</span>
The value of 'x' is 24.2 and the value of 'y' is 46.5.
To solve this, we do the following steps.
<u>Step 1:</u> Divide 'y' into 2 parts, 'a' and 'b'. 'a' would be the lower leg of the 45°-45°-90° triangle, while 'b' is the lower leg of the 30°-60°-90° triangle.<em>
</em><u>Step 2:</u> Given the hypotenuse (34) of the 30°-60°-90° triangle, solve for 'b' using the cosine of 30°.
cos30° = b/34 [adjacent over hypotenuse]
b = 34cos30° [cross-multiply]
b = 29.4
<u>Step 3:</u> Solve for the 90° leg (the side opposite the 30° angle) using the Pythagorean Theorem. We will name this leg "h" (cuz height).
l² + l² = hyp²
29.4² + h² = 34²
h² = 1156 - 864.36
√h² = √291.64
h = 17.1
<u>Step 4:</u> Solve for 'x' by using the 45°-45°-90° triangle ratio (1:1:√2). √2 would be the hypotenuse of the 45°-45°-90° triangle, while 1 would be both congruent legs.
Side 'h' is one of the legs; side 'a' is the other. Since these legs are congruent, 'a' also measures 17.1. Now all we need to do is solve for 'x', which is our hypotenuse. To do this, we simply multiply the measure of side 'h' or 'a' by √2.
x = 17.1 × √2
x = 24.2
<u>Step 5:</u> Now that we got the value of 'x', solve for 'y' by adding the measures of sides 'a' and 'b' together.<em>
</em><u /> y = a + b
y = 17.1 + 29.4
y = 46.5
And there you have it! <em>Hope this helps.</em>
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Answer B. there are any restrictions. You can represent it in any x point
