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k0ka [10]
3 years ago
13

How many different three digit locker combinations are possible if the digits are able to repeat?

Mathematics
1 answer:
VLD [36.1K]3 years ago
8 0
1000, because if it’s number 0-9 you have 10 options for the first possible number, then multiply by 10 two more time for the second and third number .but if it’s wrong I’m srry rip ;P
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Solve 9≤c+1. Graph the solution.<br><br> The solution is <br> .
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3 years ago
Find the domain and range of the graph
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domain= -1, 3

range = -1, 1

Step-by-step explanation: ok

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Write in form y=mx+b I will give brainiest to correct answer
Viktor [21]

Step-by-step explanation:

y=mx+b (m is the slope, b is the y-intercept)

To come with sope choose two points from the graph (6,20), (4,30)

Then

m=(Y2-Y1)/(X2-X1) =(4-6)/(30-20)=-1/5

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5 0
3 years ago
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What’s is the value of n? HELP ASAP PLEASE
earnstyle [38]

Answer:

The answer should be 69°

Step-by-step explanation:

Each line is being cut by a transversal, that means that the degree on the other side of it, added with the given degree will add up to 180°

1. On the right, you need to find the interior angle where 160° is outside so you subtract 180° from 160° to find the angle inside. That gives you 20°

2. On the top left you have 131° so 180°-131°=49°

Next you add the angles you have and then subtract it from 180 to get the interior angle with n° outside.

3. 20°+49°=69°

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Then you do the same thing as the beginning which would be n°+111°=180°

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So permiter=masure of all sides added together
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use associative property
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(3x+2)+(2x+5)+(4x)=3x+2+2x+5+4x
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(3x+2x+4x)+(2+5)
add like terms
(9x)+(7)
9x+7
he will use 9x+7=perimiter





7 0
3 years ago
Read 2 more answers
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