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konstantin123 [22]
3 years ago
14

The mass of a pencil is 5.44 g. The mass of a crayon is 2.145 g. How much greater is the mass of the pencil than the mass of the

crayon?
Mathematics
2 answers:
Nitella [24]3 years ago
6 0

Answer:

The mass of a pencil is 3.295 greater than the mass of the crayon.

Step-by-step explanation:

Consider the provided information.

The mass of a pencil is 5.44 g. The mass of a crayon is 2.145 g.

We need to find how much greater is the mass of the pencil than the mass of the crayon?

To find this simply subtract the mass of a crayon from mass of a pencil.

5.44-2.145

This can be written as:

5.440

<u>-2.145</u>

<u> 3.295</u>

Hence, the mass of a pencil is 3.295 greater than the mass of the crayon.

fenix001 [56]3 years ago
4 0
The pencil is 3.295 more than the crayon
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Consider the function f ( x ) = − 2 x 3 + 27 x 2 − 108 x + 9 . For this function there are three important open intervals: ( − [
Darya [45]

Answer:

<em>A=3 and B=6</em>

Step-by-step explanation:

<u>Increasing and Decreasing Intervals of Functions</u>

Given f(x) as a real function and f'(x) its first derivative.

If f'(a)>0 the function is increasing in x=a

If f'(a)<0 the function is decreasing in x=a

If f'(a)=0 the function has a critical point in x=a

As we can see, the critical points may define open intervals where the function has different behaviors.

We have

f ( x ) = - 2 x^3 + 27 x^2 - 108 x + 9

Computing the first derivative:

f' ( x ) = - 6 x^3 + 54 x - 108

We find the critical points equating f'(x) to zero

- 6 x^3 + 54 x - 108=0

Simplifying by -6

x^2 -9 x +18=0

We get the critical points

x=3,\ x=6

They define the following intervals

(-\infty,3),\ (3,6),\ (6,+\infty)

Thus A=3 and B=6

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3 years ago
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Step-by-step explanation:

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