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Neporo4naja [7]
3 years ago
6

UW = m and WX = y + 14 Write an expression for UX.

Mathematics
1 answer:
kifflom [539]3 years ago
6 0

\bf \begin{cases} UW = m\\ WX = y+14 \end{cases} ~\hfill WX = y+14\implies \boxed{W=\cfrac{y+14}{X}} \\\\\\ \stackrel{\textit{doing substitution on the 1st equation}}{UW = m\implies U=\cfrac{m}{W}\implies }U=\cfrac{m}{\frac{y+14}{X}}\implies U=\cfrac{\frac{m}{1}}{\frac{y+14}{X}} \\\\\\ U=\cfrac{m}{1}\cdot \cfrac{X}{y+14}\implies U=\cfrac{mX}{y+14}\implies \stackrel{\textit{multiplying both sides by X}}{UX=\cfrac{mX^2}{y+14}}

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Simplify the expression.<br><br><br> Write your answer without negative exponents.
Phoenix [80]

Answer:

-5/ (x^19 * y^12)

Step-by-step explanation:

-15x^-10 * y ^ -3 * x^-9 * y^-9/3 (It's writing it like this.)

15 and 3 have a GCF of 3.

-5x^-10 * y^-3 * x^-9 * y^-9/1

Reduce similar occurrences. *twice in a row*

-5x^(-10 + (-9)) * y^(-3 + (-9))/1

Remove extra signs *twice in a row*

-5x^(-10 - 9) * y^(-3 - 9)/1

Remove extraneous 1.

-5x^(-10 - 9) * y^(-3 - 9)

Add integers.

-5x^-19 * y^-12

Negative powers change multiplication to division.

-5 / (x^19 * y^12) is the final answer.

Even with that, the simplified answer wouldn't have negative exponents because of the negative powers rule.

8 0
2 years ago
a counter top is in the shape of a trapezoid. The lengths of the bases are 70 1/2 and 65 1/2 inches long. The area of the counte
nekit [7.7K]
For the trapezoid, the equation used to solve for the area is,
                           A = (0.5)(b₁ + b₂)(h)
where b₁ and b₂ are the measure of the bases and h is the height. Substituting the known values above,
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7 0
3 years ago
Determine whether the following lines represented by the vector equations below intersect, are parallel, are skew, or are identi
KiRa [710]

Answer:

r(t) and s(t) are parallel.

Step-by-step explanation:

Given that :

the  lines represented by the vector equations are:

r(t)=⟨1−t,3+2t,−3t⟩

s(t)=⟨2t,−3−4t,3+6t⟩

The objective is to determine if the following lines represented by the vector equations below intersect, are parallel, are skew, or are identical.

NOTE:

Two lines will be parallel if \dfrac{x_1}{x_2}= \dfrac{y_1}{y_2}= \dfrac{z_1}{z_2}

here;

d_1 = (-1, \ 2, \ -3)

Thus;

r(t) = \dfrac{x-1}{-1} = \dfrac{y-3}{2}=\dfrac{z-0}{-3} = t

d_2 =(2, \ -4, \  +6)

s(t) = \dfrac{x-0}{2} = \dfrac{y+5}{-4}=\dfrac{z-3}{6} = t

∴

\dfrac{d_1}{d_2}= \dfrac{-1}{2} = \dfrac{2}{-4}= \dfrac{-3}{-6}

Hence, we can conclude that r(t) and s(t) are parallel.

6 0
3 years ago
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tankabanditka [31]
It would be t=0.8, mainly bc you subtract two from six , that reduces it to four 
then you divide four by five and it should give you your answer
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Answer:

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2 years ago
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