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Alex17521 [72]
3 years ago
12

He greatest common factor. 46x^5. 10x^3

Mathematics
1 answer:
ch4aika [34]3 years ago
8 0
The answer to this question is 460x^8
46x^5*10x^3
460x^5x^3
460x^8


I hope this helps!!!!!!!
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Marco is carrying two cylinder-shaped cans. Each can has the same height
Dafna11 [192]

Answer:

Choice D

Step-by-step explanation:

The Cavalieri's principle states that if two or more solids have identical cross-sectional area as well as height, then the solids will have equal volume.

Therefore, the volumes of the cylinders are the same

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RUDIKE [14]
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Given: LMNP is a square A, B midpoints of LM and PN Q ∈ AB m∠LPQ = 45° Find: m∠PQN
lisov135 [29]
Since A and B are the midpoints of ML and NP, we can say that AB is parallel to MN and LP. In order to find ∠PQN, we can work with the triangles PQB and NQB. According to SAS (Side-Angle-Side) principle, these triangles are congruent. BQ is a common side for these triangles and NB=BP and the angle between those sides is 90°, i.e, ∠NBQ=∠PBQ=90°. After finding that these triangles are equal, we can say that ∠BNQ is 45°. From here, we easily find <span>∠PQN. It is 180 - (</span>∠QNP + ∠NPQ) = 180 - 90 = 90°

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3 years ago
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Rzqust [24]
Hope This Helped and GOOD LUCK!!!!!!! :D

3 0
3 years ago
A firework is launched into the air from ground level with an initial velocity of 128 ft/s. If acceleration due to gravity is –1
Hitman42 [59]

Answer:

h = 256 feet

Step-by-step explanation:

Given that,

The initial velocity of firework, v = 128 ft/s

The acceleration due to gravity is-16 ft/s².

We need to find the maximum height reached by the firework.

The equation for the firework is :

h(t) = -16t^2 + 128t

To find the vertex's x-coordinate, we can use  

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h(t) = -16(4)^2 + 128(4)\\\\h(t)=256\ ft

So, the maximum height reached by the firework is 256 feet.

6 0
2 years ago
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