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jeyben [28]
3 years ago
10

In a game, your character cleverly places an electronic bug on an unsuspecting felon's jacket to track his movements. The bug tr

ansmits data on
a real-time basis that your character can read on her handheld device. The handheld device appears on the screen with the felon marked as a
flashing red dot. What component of the visual interface does the handheld device represent?
A map
B. score
c lives
D.character
Computers and Technology
2 answers:
polet [3.4K]3 years ago
7 0

Answer:

a. map is the answer

Papessa [141]3 years ago
5 0

The component of the visual interface does the handheld device represent map.

A. Map

<u>Explanation:</u>

Since the character has placed a bug to track the felon’s movement in order to accomplish his mission, the handheld device marks out the felon’s location. The bug indicates the felon as a red dot and it shows up on the handheld device. With this, the character could capture the felon.

On the game’s HOD(Heads On Display), the handheld device is shown mostly on corner. So the handheld device indicates the map as a component of visual user interface.

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Create a program that includes a function called toUpperCamelCase that takes a string (consisting of lowercase words and spaces)
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Answer:

#include<iostream>

using namespace std;

//method to remove the spaces and convert the first character of each word to uppercase

string

toUpperCameICase (string str)

{

string result;

int i, j;

//loop will continue till end

for (i = 0, j = 0; str[i] != '\0'; i++)

{

 if (i == 0)       //condition to convert the first character into uppercase

  {

  if (str[i] >= 'a' && str[i] <= 'z')   //condition for lowercase

  str[i] = str[i] - 32;   //convert to uppercase

  }

if (str[i] == ' ')   //condition for space

  if (str[i + 1] >= 'a' && str[i + 1] <= 'z')   //condition to check whether the character after space is lowercase or not

  str[i + 1] = str[i + 1] - 32;   //convert into uppercase

if (str[i] != ' ')   //condition for non sppace character

  {

  result = result + str[i];   //append the non space character into string

  }

}

//return the string

return (result);

}

//driver program

int main ()

{

string str;

char ch;

//infinite loop

while (1)

{

fflush (stdin);

//cout<< endl;

getline (cin, str);   //read the string

//print the result

//cout<< endl << "Q";

// cin >> ch; //ask user to continue or not

ch = str[0];

if (ch == 'q' || ch == 'Q')   //is user will enter Q then terminatethe loop

  break;

cout << toUpperCameICase (str);

cout << endl;

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8 0
3 years ago
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Answer

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Explanation:

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Answer:

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Let a,b be two numbers.

c=a+b;

print(c);

But, if you want to find the sum of more numbers, you can use any loop like for, while or do-while as follows:

Let a be the variable where the input numbers are stored.

while(f==1)

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printf(“Enter number”);

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scanf(“Take the input into the variable f”);

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print(Sum)

Explanation:

hi there answer is given mar me as brainliest

5 0
3 years ago
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