Answer:
The solution is as follows.
class LFilters implements Lock {
int[] lvl;
int[] vic;
public LFilters(int n, int l) {
lvl = new int[max(n-l+1,0)];
vic = new int[max(n-l+1,0)];
for (int i = 0; i < n-l+1; i++) {
lvl[i] = 0;
}
}
public void lock() {
int me = ThreadID.get();
for (int i = 1; i < n-l+1; i++) { // attempt level i
lvl[me] = i;
vic[i] = me;
// rotate while conflicts exist
int above = l+1;
while (above > l && vic[i] == me) {
above = 0;
for (int k = 0; k < n; k++) {
if (lvl[k] >= i) above++;
}
}
}
}
public void unlock() {
int me = ThreadID.get();
lvl[me] = 0;
}
}
Explanation:
The code is presented above in which the a class is formed which has two variables, lvl and vic. It performs the operation of lock as indicated above.
Answer:
The answer to this question is "Password".
Explanation:
In computer science, any User's computer and networks and server is secured with the password to access all we use the password. for example, if we want to access any WiFi system or any User's computer. Then we will insert the password. If the password is wrong so we can't access the WiFi system or User's computer. similarly, If we want to access any server so we must know about the password. Then we use the server and change it's setting.
So the password is the primary means of authentication for all User's.
Answer:
if(revenue.cents - expenses.cents < 0){
profit.dollars = revenue.dollars - expenses.dollars - 1;
profit.cents = 1 - revenue.cents - expenses.cents;
}
else{
profit.dollars = revenue.dollars - expenses.dollars;
profit.cents = revenue.cents - expenses.cents;
}
Explanation:
We know that profit is given as: revenue - expenses from the question.
From the given expression above;
if(revenue.cents - expenses.cents < 0)
then profit.dollar will be revenue.dollars - expenses.dollars - 1; the 1 is to be carry over to the cent part. And the profit.cent will be 1 - revenue.cents - expenses.cents;
else the profit.dollars and the profit.cent is computed directly without needing to carry over:
profit.dollars = revenue.dollars - expenses.dollars;
profit.cents = revenue.cents - expenses.cents;
I think it’s B if not it’s D both are similar
Answer:
public static void quad(double a, double b, double c) {
double D = (Math.pow(b, 2)) - (4 * a * c);
if (D<0){
System.out.println("no real solutions");
}
}
Explanation:
The code snippet above implements the function in Java programming language
As required by the question, the line double D = (Math.pow(b, 2)) - (4 * a * c); evaluates b squared" - 4ac and assignes the value to the variable D
An if statement is used to test if D is less than 0, if this is true the message no real solutions is printed
