The question did not show the original vertices of A, B, and C.
Generally, for a triangle ABC that is dilated by a scale factor of four to form triangle A'B'C', the coordinates of vertices A', B', C' are:
For A(x, y)
The coordinate of vertex A' will be A' (4x, 4y)
For B(x, y)
The coordinate of vertex B' will be B' (4x, 4y)
For C(x, y)
The coordinate of vertec C' will be C' (4x, 4y)
Answer
C. Sam owes his dad $7.50
Step-by-step explanation:
because none are correct but tat is te closetes one
L = 22 because area equals length times width. So if you divide the area (143) by the width (6.5) you get 22
Answer: The missing statements are,
In first blank: ∠2≅∠1
In second blank: AC≅AC
In third blank: Reflexive
Step-by-step explanation:
Since, The hypotenuse angle theorem states that if the hypotenuse and an acute angle of one right triangle are congruent to the hypotenuse and an acute angle of another right triangle, then the two triangles are congruent to each other.
Here, given:
∠D and ∠B are right angles.
DC ║ AB
Prove: Δ ADC ≅ Δ CBA
Statement Reason
1.∠D and ∠B are right angles 1. Given
2. ∠2 ≅ ∠1 2. If lines are parallel then interior angles
are equal
3. AC≅AC 3. Reflexive
4.Δ ADC ≅ Δ CBA 4. Hypotenuse angle theorem
