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djverab [1.8K]
3 years ago
7

What is the formula to solve midpoint

Mathematics
1 answer:
nataly862011 [7]3 years ago
3 0

Answer:

<u>(x1 + x2)</u> , <u>(y1+y2)</u>

   2              2

Step-by-step explanation:

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Use the Statistical Applet: Normal Density Curve to answer the question.Set the mean and standard deviation to 0 and 5 , respect
SVEN [57.7K]

Answer:

z=-1.995

And if we solve for a we got

a=10 -1.995*5=0.025

Step-by-step explanation:

For this case we have the initial case we have a normal distribution given :

X \sim N(0,5)  

Where \mu=0 and \sigma=5

And from the info of the problem we know that:

P(X

We can verify this using the z score formula given by:

z= \frac{x\mu}{\sigma}

And if we replace we got:

P(X

Now we have another situation for a new random variable X with a new distribution given by:

X \sim N(10,5)  

Where \mu=10 and \sigma=5

For this part we want to find a value a, such that we satisfy this condition:

P(X>a)=0.977   (a)

P(X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.023 of the area on the left and 0.977 of the area on the right it's z=-1.995. On this case P(Z<-1.995)=0.023 and P(z>-1.995)=0.977

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=-1.995

And if we solve for a we got

a=10 -1.995*5=0.025

4 0
3 years ago
What is the volatile acid/alkalinity relationship in a digester if the alkalinity is 2400 mg/L and the volatile acids are 90 mg/
damaskus [11]

The volatile acid/alkalinity relationship in a digester is volatile acid/alkalinity = 3/80

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more variables and numbers.

Ratio of volatile acid to alkalinity = 90 mg/L ÷ 2400 mg/L = 3/80

The volatile acid/alkalinity relationship in a digester is volatile acid/alkalinity = 3/80

Find out more on equation at: brainly.com/question/2972832

#SPJ1

8 0
2 years ago
How do I make it go to the other side
kow [346]

Answer:

rotate IT very easy mark me as brainalist

6 0
2 years ago
Read 2 more answers
If 3x-y=123x−x=123, x, minus, y, equals, 12, what is the value of \frac{8^x}{2^y} 2 y 8 x ​ start fraction, 8, start superscript
nlexa [21]

Answer:

\frac{8^x}{2^y} = 4096

Step-by-step explanation:

Rules:

  1. \frac{a^m}{a^n}=a^{m-n}
  2. a^m\times a^n= a^{m+n}
  3. (a^m)^n=a^{m\times n}

Given that,

3x-y =12

Therefore

\frac{8^x}{2^y}

=\frac{(2^3)^x}{2^y}  [ since 8=2^3 ]

=\frac{2^{3x}}{2^y}   [ applying 3rd rule]

=2^{3x-y} [ applying 2nd rule]

=2^{12}   [ since 3x-y =12]

=4096

3 0
3 years ago
Whats 107 over 1000 as a decimal​
ivann1987 [24]

Step-by-step explanation:

107 / 1000 = 0.107

6 0
3 years ago
Read 2 more answers
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