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const2013 [10]
3 years ago
10

Help please...........

Mathematics
1 answer:
IgorC [24]3 years ago
4 0
F(x) = 5*x - 12

f(2) = 5*2 - 12  .... replace every x with 2, then use PEMDAS to simplify

f(2) = 10 - 12

f(2) = -2

The final answer is -2, which is choice C

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15 points! The data set shows the weights of pumpkins, in pounds, that are chosen for a photograph in a farming magazine. The re
vladimir2022 [97]

Answer:

Step-by-step explanation:

a). Mean of the given data set = \frac{32+28+18+40+22}{5}

                                                  = 28

b).   x                     x-\overline{x}               (x-\overline{x})^2

     32          32-28 = 4                    16

     28          28 - 28 = 0                  0

     18           18 - 28 = -10                100

     40          40 - 28 = 12                 144

     22          22 - 28 = -6                 36

                                                 \sum({x-\overline x})^2 =  296          

c). Standard deviation = \sqrt{\frac{\sum (x-\overline{x})^2}{n}}

                                     = \sqrt{\frac{296}{5} }

                                     = 7.69

d). Mean of the new set of weights = \frac{32+33+34+35+36}{5}

                                                          = 34

   Since mean of the data set is more close to each data, standard deviation will be less than the deviation given in part (c).

7 0
3 years ago
A safety officer wants to prove that μ = the average speed of cars driven by a school is less than 25 mph. Suppose that a random
melomori [17]

Answer:

t=\frac{24-25}{\frac{2.2}{\sqrt{14}}}=-1.70    

p_v =P(t_{(13)}  

If we compare the p value and the significance level given \alpha=0.05 and we can see that p_v>\alpha so we can conclude that we have enough evidence to FAIL reject the null hypothesis, so we can't conclude that the true average speed is lower than 25 mph at 5% of signficance.  

Step-by-step explanation:

Data given and notation  

\bar X=24 represent the sample mean

s=2.2 represent the sample standard deviation

n=14 sample size  

\mu_o =25 represent the value that we want to test

\alpha=0.05 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true mean for the average speed is lower than 25 mph, the system of hypothesis would be:  

Null hypothesis:\mu \geq 25  

Alternative hypothesis:\mu < 25  

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{24-25}{\frac{2.2}{\sqrt{14}}}=-1.70    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=14-1=13  

Since is a one side test the p value would be:  

p_v =P(t_{(13)}  

Conclusion  

If we compare the p value and the significance level given \alpha=0.05 and we can see that p_v>\alpha so we can conclude that we have enough evidence to FAIL reject the null hypothesis, so we can't conclude that the true average speed is lower than 25 mph at 5% of signficance.  

7 0
3 years ago
Pls helppp
Alexxandr [17]

Answer:

The answer is 4/10

Step-by-step explanation:

If you add all marbles in both bags it equals 40. There are 10 pink marbles in both so 40 / 10 is 4 and the denominator would be 10. 4/10

8 0
3 years ago
Read 2 more answers
INTRODUCTION TO FUNCTION COMMON CORE ALGEBRA II HOMEWORK <br> HELP SOMEONE PLEASE ‼️‼️‼️‼️‼️‼️‼️‼️
umka2103 [35]

Using the concept of function, it is found that:

  • Graphs B, C, D and F are functions.
  • Graphs A and E are not functions.

-----------------------------

  • In a function, one value of the input can be related to only one value of the output.
  • In a graph, it means that for <u>each value of x(horizontal axis), there can only be one respective value of y(vertical axis). </u>That is, if a vertical line is traced at a value of x, it can cross the function only once, that is, there cannot be points aligned vertically.
  • In graphs B, C, D and F, it can be seen that <u>for each x value, there is only one respective y-value</u>, thus, they are functions.
  • In graphs A and E, for <u>values of x,</u> such as x = 3 for both, there are <u>two respective values of y</u>, thus they are not functions.

A similar problem is given at brainly.com/question/12463448

8 0
3 years ago
PLS HELP ME!!!!!!!!!!!
jolli1 [7]

Answer:

great

Step-by-step explanation:

8 0
3 years ago
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