Question

15 points! The data set shows the weights of pumpkins, in pounds, that are chosen for a photograph in a farming magazine. The rest of the question is on the screenshot. Please help!

Answer 1

Answer:

Step-by-step explanation:

a). Mean of the given data set = $\frac{32+28+18+40+22}{5}$

                                                  = 28

b).   x                     $x-\overline{x}$               $(x-\overline{x})^2$

     32          32-28 = 4                    16

     28          28 - 28 = 0                  0

     18           18 - 28 = -10                100

     40          40 - 28 = 12                 144

     22          22 - 28 = -6                 36

                                                 $\sum({x-\overline x})^2$ =  296          

c). Standard deviation = $\sqrt{\frac{\sum (x-\overline{x})^2}{n}}$

                                     = $\sqrt{\frac{296}{5} }$

                                     = 7.69

d). Mean of the new set of weights = $\frac{32+33+34+35+36}{5}$

                                                          = 34

   Since mean of the data set is more close to each data, standard deviation will be less than the deviation given in part (c).