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shutvik [7]
3 years ago
12

The image of a parabolic lens is projected onto a graph. The image crosses the x-axis at –2 and 3. The point (–1, 2) is also on

the parabola. Which equation can be used to model the image of the lens?
y = -1/5 (x – 2)(x + 3)
y = -1/3(x – 2)(x + 3)
y = -1/2 (x + 2)(x – 3)
y = 1/4 (x + 2)(x – 3)

Mathematics
2 answers:
Rus_ich [418]3 years ago
7 0

y = (x + 2)(x – 3)  

this is 100% used to model the image of the lens.

answer: c (on ed. quiz)


Nezavi [6.7K]3 years ago
4 0
For x-intercepts "b" and "c", a quadratic can be written as
  y = a(x -b)(x -c)

You know the x-intercepts, so you can write the equation as
  y = a(x +2)(x -3) . . . . . . eliminates the first two answer choices

Substituting (x, y) = (-1, 2), you have
  2 = a(-1+2)(-1-3) = -4a
Then dividing by -4 gives
  -2/4 = a = -1/2 . . . . . corresponds to the third answer choice

The appropriate selection is
  y = -1/2 (x + 2)(x - 3)

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Find an equation for the line that passes through the point (-4, 10) and (16, -2)
Crank

Answer:

y = 3/5x + 62/5

Step-by-step explanation:

Equation of a line with two points is

m = y - y_1 / x - x _1

m = y_2 - y_1 / x_2 - x _1

Equating both

y - y_1 / x - x_1 = y_2 - y_1 / x_2 - x_1

Using what we are provided with

(-4 , 10)(16 , -2)

x_1 = -4

y_1 = 40

x_2 = 16

y_2 = -2

Imputing the values

10 - (-2) / 16 - (-4) = y - 10 / x - (-4)

10 + 2 /16 + 4 = y - 10 / x + 4

12 / 20 = y - 10 / x + 4

Lets cross multiply

12 ( x + 4) = 20(y - 10)

Open the brackets

12x + 48 = 20y - 200

12x + 48 + 200 = 20y

12x + 248 = 20y

Following this equation of line

y = mx + C

20y = 12x + 248

Let's divide through by 20 to get y.

20y / 20 = 12x + 248 / 20

y = 12x + 248 / 20

We can separate it by

y = 12x / 20 + 248 / 20

y = 3/5x + 62/5

Therefore, the equation of the line is

y = 3/5x + 62/5

3 0
3 years ago
Given the definitions of f(x) and g(x) below, find the value of g(f(6)).
Fofino [41]
3 because it is a better Dona a toon
8 0
3 years ago
According to the scatterplot below, which statement is correct? A graph titled Courses Completed versus Remaining Credits Needed
kondaur [170]

Answer:

Option B.

Step-by-step explanation:

It is given that a graph titled Courses Completed versus Remaining Credits Needed to Graduate has courses completed on the x-axis and Credits need to graduate on the y-axis.

Points plotted are (4, 110), (8, 76), (16, 63), (20, 53), (24, 33).

Since, x-axis represents the courses completed, therefore the input, or independent variable is courses completed.

Since, y-axis represents the Credits need to graduate, therefore the output, or dependent variable is Credits need to graduate.

Therefore, the correct option is B.

6 0
3 years ago
Read 2 more answers
Evaluate the function at x = –2.<br><br><br><br> y = 0<br><br> y = 3<br><br> y = –4<br><br> y = 2
dezoksy [38]

When x=-2, y is equal to 3

4 0
3 years ago
??? Need help please
elena55 [62]
Slope is -3
Explanation
Take points
(4,3) and (6,-3)
-3-(3)
———= -6/2 which equals -3
6-4
7 0
2 years ago
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