A polynomial function with a leading coefficient

A company sells tubs of yogurt for 75¢ each. twenty percent of this is profit for the food company. how much profit does the com

inn [45]

.15

75/5=15

20 percent of 75 is 15

20 percent = 15

40 percent = 30

60 percent = 45

80 percent = 60

100 percent = 75

4 0

3 years ago

The formula for computing compound interest for a principal P that is invested at an annual rate r and compounded annually is gi

maria [59]

9514 1404 393

Answer:

r ≈ 6%

Step-by-step explanation:

Solving for r when n=2, we have ...

$A=P(1+r)^2\\\\\dfrac{A}{P}=(1+r)^2\\\\\sqrt{\dfrac{A}{P}}=1+r\\\\\boxed{r=\sqrt{\dfrac{A}{P}}-1}$

For the given values of A and P, the value of r is ...

$r=\sqrt{\dfrac{5600}{5000}}-1=\sqrt{1.12}-1\approx 1.0583-1\\\\\boxed{r\approx 6\%}$

8 0

3 years ago

X+(-3)=-7 Solve the equation and enter the value of x below

Phoenix [80]

Answer:

x=-4

Step-by-step explanation:

x+(-3)=-7

x-3=-7

x=-7+3=3-7

x=-4

3 0

3 years ago

Read 2 more answers

In a class, every student knows French or German (or both). 15 students know French, and 17 students know German.

leva [86]

Answer:
32 students

Explanation:
We are given that:
Students in the class can either speak French, German or both
15 students know French
17 students know German

Now, the maximum number in the class can be calculated by assuming that no student can speak both languages.
This means that the number of students will be the summation of those who know French only (15) and those who know German only (17)

In this case:
the maximum number of students = 15 + 17 = 32 students

Hope this helps :)

4 0

3 years ago

A restaurant operator in Accra has found out that during the lockdown,if she sells a plate of her food for Ghc 20 each,she can s

ella [17]

The demand equation illustrates the price of an item and how it relates to the demand of the item.

The slope of the demand function is -1/2
The equation of the demand function is: $R(x) = (300 - 10x) \times (20 + 5x)$
The price that maximizes her revenue is: Ghc 85

From the question, we have:

$Plates = 300$

$Price = 20$

The number of plates (x) decreases by 10, while the price (y) increases by 5. The table of value is:

$\begin{array}{cccccc}x & {300} & {290} & {280} & {270} & {260} \ \\ y & {20} & {25} & {30} & {35} & {40} \ \end{array}$

The slope (m) is calculated using:

$m = \frac{y_2 - y_1}{x_2 - x_1}$

So, we have:

$m = \frac{25-20}{290-300}$

$m = \frac{5}{-10}$

$m = -\frac{1}{2}$

The equation of the demand is as follows:

The initial number of plates (300) decreases by 10 is represented as: (300 - 10x).

Similarly, the initial price (20) increases by 5 is represented as: (20 + 5x).

So, the demand equation is:

$R(x) = (300 - 10x) \times (20 + 5x)$

Open the brackets to calculate the maximum revenue

$R(x) =6000 + 1500x - 200x - 50x^2$

$R(x) =6000 + 1300x - 50x^2$

Equate to 0

$6000 + 1300x - 50x^2 =0$

Differentiate with respect to x

$1300 - 100x =0$

Collect like terms

$100x =1300$

Divide by 100

$x =13$

So, the price at maximum revenue is:

$Price= 20 + 5x$

$Price= 20 + 5 * 13$

$Price= 85$

In conclusion:

The slope of the demand function is -1/2
The equation of the demand function is: $R(x) = (300 - 10x) \times (20 + 5x)$
The price that maximizes her revenue is: Ghc 85