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grigory [225]
3 years ago
8

The table shows the toothbrush production rate of One machine. Toothbrush Production Minutes 2 4 6 8 10 Toothbrushes 140 280 | 4

20 | 560 700 Which of these describes the production rate per minute? 30 toothbrushes 50 toothbrushes 70 toothbrushes d 140 toothbrushes​
Mathematics
1 answer:
Klio2033 [76]3 years ago
5 0

9514 1404 393

Answer:

  c)  70 toothbrushes per minute

Step-by-step explanation:

The table tells you that production is 140 toothbrushes in 2 minutes. Dividing toothbrushes by minutes gives you the "per minute" value:

  (140 toothbrushes)/(2 minutes) = (140/2) toothbrushes/minute

  = 70 toothbrushes/minute

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G(x)= -8x<br> H(x)=x^2 +3x+2
djverab [1.8K]

Answer:

g=8

i dont know sorry... ......

6 0
3 years ago
8,9,8,11<br> Mean:<br> Median:<br> Mode:<br> Range
Finger [1]
Mean: add all numbers together and divide by the amount of numbers there are.
8 + 9 + 8 + 11 = 36
36/4 = 9
mean = 9

Median: Find the middle number. Since in this case it has an even amount of numbers, add the two middle numbers and divide by 2
8 + 9 = 15
15/2 = 7.5
median = 7.5

Mode: The number that shows up the most 
Mode  = 8

Range: Subtract the smallest number from the largest number
11 - 8 = 3
Range = 3

hope this helps
7 0
3 years ago
Read 2 more answers
The segments shown below could form a triangle.
Rina8888 [55]

Answer:

A. True

Step-by-step explanation:

The Triangle Inequality Theorem says that the sum of any two sides must be greater than the third side. Let's see if this is true.

a + b

9 + 1 = 10>9

a + c

9 + 9 = 18>1

c + b

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5 0
3 years ago
The table shows the number of boys and girls who signed up for certain summer classes.
Makovka662 [10]

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Step-by-step explanation:

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7 0
2 years ago
Find the polynomial f(x) of degree 3 with real coefficients that has a y-intercept of 60 and zeros 3 and 1+3i.
Sauron [17]

\bf \begin{cases} x=3\implies &x-3=0\\ x=1+3i\implies &x-1-3i=0\\ x=1-3i\implies &x-1+3i=0 \end{cases} \\\\[-0.35em] ~\dotfill\\\\ (x-3)(x-1-3i)(x-1+3i)=0 \\\\\\ (x-3)\underset{\textit{difference of squares}}{([x-1]-3i)([x-1]+3i)}=0\implies (x-3)([x-1]^2-[3i]^2)=0 \\\\\\ (x-3)([x^2-2x+1]-[3^2i^2])=0\implies (x-3)([x^2-2x+1]-[9(-1)])=0

[ correction added, Thanks to @stef68 ]

\bf (x-3)([x^2-2x+1]+9)=0\implies (x-3)(x^2-2x+10)=0 \\\\\\ x^3-2x^2+10x-3x^2+6x-30=0\implies x^3-5x^2+16x-30=f(x) \\\\\\ \stackrel{\textit{applying a translation with a -2f(x)}}{-2(x^3-5x^2+16x-30)=f(x)}\implies -2x^3+10x^2-32x+60=f(x)

5 0
3 years ago
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