Answer:
The specific question is not stated, however the general idea is given in the attached picture. The electric field in each region can be found by Gauss’ Law.
at r < R:
Since the solid sphere is conducting, the total charge Q is distributed over the surface, and the electric field inside the sphere is zero.
E = 0.
at R < r < 2R:
The electric field can be found by Gauss’ Law as in the attachment. The green pencil shows this exact region.
at 2R < r:
The electric field can again be found by Gauss’ Law, the blue pencil shows the calculations for this region.
Explanation:
Gauss’ Law is straightforward when applied to spheres. The area of the sphere is 
, and the enclosed charge is given in the question as Q for the inner sphere, and 2Q for the whole system.
Answer:
It will apply the greatest pressure of an area of 1.
Explanation:
To find pressure use the formula P = F/A
P = 100/1
P = 100
10.7 rad/s is the final angular velocity of the stick.
Given:
Mass of the stick = 4.42 kg
Length of the stick = 1.23m
Force of impulse (I) = 12.8 N s
The linear velocity of the stick, 
Therefore, the final linear velocity of the stick is 2.89 m/s
∴
Therefore, 10.7 rad/s is the final angular velocity of the stick.
Learn more about linear velocity here:
brainly.com/question/15154527
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Explanation:
It is given that,
Initial speed of a golfer, u = 29 m/s
If it travels the maximum possible distance before landing. It means that it is projected at an angle of 45 degrees.
(a) We need to find the time spent by the ball in the air. It can be calculated by using second equation of motion.
Here,
a = -g
s = 0 (it is displacement and it is equal to 0 as the ball lands on the green).
So,
So, it will take 4.184 seconds in the air.
(b) let x is the longest hole in one that the golfer can make if the ball does not roll when it hits the green. It can be given by :
Hence, this is the required solution.
