Answer:
2 m/s^2
Explanation:
from the question
v=15 m/s
t=7.5
a=?
from the first equation of motion
v=u+at
where,
v=final velocity
u=initial velocity
a=acceleration
t=time
from the question (u) will be zero because the body started at rest
v=u+at
15=(0)+a×7.5
15=7.5a
a=15/7.5
a=2 m/s^2
The strength of the gravitational force between two objects depend on two factors, mass and distance.
We actually don't need to know how far he/she is standing from the net, as we know that the ball reaches its maximum height (vertex) at the net. At the vertex, it's vertical velocity is 0, since it has stopped moving up and is about to come back down, and its displacement is 0.33m. So we use v² = u² + 2as (neat trick I discovered just then for typing the squared sign: hold down alt and type 0178 on ur numpad wtih numlock on!!!) ANYWAY....... We apply v² = u² + 2as in the y direction only. Ignore x direction.
IN Y DIRECTION: v² = u² + 2as 0 = u² - 2gh u = √(2gh) (Sub in values at the very end)
So that will be the velocity in the y direction only. But we're given the angle at which the ball is hit (3° to the horizontal). So to find the velocity (sum of the velocity in x and y direction on impact) we can use: sin 3° = opposite/hypotenuse = (velocity in y direction only) / (velocity) So rearranging, velocity = (velocity in y direction only) / sin 3° = √(2gh)/sin 3° = (√(2 x 9.8 x 0.33)) / sin 3° = 49 m/s at 3° to the horizontal (2 sig figs)
The acceleration of the car is determined as 0.626 m/s².
<h3>
What is acceleration?</h3>
The acceleration of an object is the change in velocity of the object with time.
a = Δv/t
where;
- Δv is change in velocity
- t is the time of motion
Substitute the given parameters and solve for the acceleration.
v = 14 mph = 6.258 m/s
a = (6.258 m/s) / (10 s)
a = 0.626 m/s²
Thus, the acceleration of the car is determined as 0.626 m/s².
Learn more about acceleration here: brainly.com/question/14344386
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Answer: The correct answer is 912 A