Answer:
−5c5−15a−25b+10
Step-by-step explanation:
13+2−5−15a−25b−5c5
=13+2+−5+−15a+−25b+−5c5
Combine Like Terms:
=13+2+−5+−15a+−25b+−5c5
=(−5c5)+(−15a)+(−25b)+(13+2+−5)
=−5c5+−15a+−25b+10
Answer:
=−5c5−15a−25b+10
The answer is (-21, 13) for The second endpoint.
Let's start by calling the known endpoint L and the unknown K. We'll call the midpoint M. In order to find this, we must first note that to find a midpoint we need to take the average of the endpoints. To do this we add them together and then divide by 2. So, using that, we can write a formula and solve for each part of the k coordinates. We'll start with just x values.
(Kx + Lx)/2 = Mx
(Kx + 1)/2 = -10
Kx + 1 = -20
Kx = -21
And now we do the same thing for y values
(Ky + Ly)/2 = My
(Ky + 7)/2 = 10
Ky + 7 = 20
Ky = 13
This gives us the final point of (-21, 13)
The Answer to this problem is BN=3.8 Units.
9514 1404 393
Answer:
0
Step-by-step explanation:
The two expressions for her salary can be equated:
2h +4 = 4 +4h
0 = 2h . . . . . . . . subtract 2h+4 from both sides
h = 0 . . . the husband's salary is zero dollars per month
Answer:
The area of this sector is 224*pi cm² or approximately 703.72 cm²
Step-by-step explanation:
In order to calculate the area of a sector for which we have an angle in radians, we need to apply a rule of three in such a way that pi*r² is related to 2*pi radians in the same proportion as the given angle is related to the area of the sector we want to find. This is shown below:
2*pi rad -> pi*r² unit²
angle rad -> sector area unit²
2*pi / angle = pi*r² / (sector area)
2*pi*(sector area) = pi*r²*angle
sector area = [pi*r²*angle]/2*pi
sector area = r²*angle/2 unit²
Applying the data from the problem, we have:
sector area = [(16)²*(7*pi/4)]/2 = [256*(7*pi/4)]/2 = 64*7*pi/2 = 32*7*pi = 224*pi
sector area = 224*pi cm²
sector area = 703.72 cm²
