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vova2212 [387]
3 years ago
5

Mark invests $6,700 in an online savings account which gives 4.2% simple annual interest. He also invests $6,000 in a savings ac

count at his local bank which gives 6.9% simple annual interest. After fifteen years how much more interest will it have earned, to the nearest dollar?
Mathematics
1 answer:
dalvyx [7]3 years ago
5 0

Answer:

$4,221.00 for online and 6,210.00 for the instore

Step-by-step explanation:

Calculation:

First, converting R percent to r a decimal

r = R/100 = 4.2%/100 = 0.042 per year.

Solving our equation:

A = 6700(1 + (0.042 × 15)) = 10921

A = $10,921.00

The total amount accrued, principal plus interest, from simple interest on a principal of $6,700.00 at a rate of 4.2% per year for 15 years is $10,921.00.

Calculation:

First, converting R percent to r a decimal

r = R/100 = 6.9%/100 = 0.069 per year.

Solving our equation:

A = 6000(1 + (0.069 × 15)) = 12210

A = $12,210.00

The total amount accrued, principal plus interest, from simple interest on a principal of $6,000.00 at a rate of 6.9% per year for 15 years is $12,210.00.

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Troyanec [42]
\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\

\begin{array}{rllll} 
% left side templates
f(x)=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
y=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
f(x)=&{{  A}}\sqrt{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}}(\mathbb{R})^{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}} sin\left({{ B }}x+{{  C}}  \right)+{{  D}}
\end{array}

\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\\\
\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\
\end{array}

\bf \begin{array}{llll}


\bullet \textit{ vertical shift by }{{  D}}\\
\qquad if\ {{  D}}\textit{ is negative, downwards}\\\\
\qquad if\ {{  D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{  B}}}
\end{array}

now, with that template in mind, let's take a peek at this function

\bf \begin{array}{lllcclll}
y=&2(&1x&-2)^2&-4\\
&\uparrow &\uparrow &\uparrow &\uparrow \\
&A&B&C&D
\end{array}\\\\
-----------------------------\\\\
A\cdot B=2\impliedby \textit{shrunk by a factor of 2, of half-size}\\\\
\cfrac{C}{B}= \cfrac{-2}{1}\implies -2\impliedby \textit{horizontal right shift of 2 units}\\\\
D=-4\impliedby \textit{vertical down shift of 4 units}

so, the graph of y=2(x-2)²-4, is really the same graph of y=x², BUT, narrower, and moved about horizontally and vertically
8 0
3 years ago
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What is the correct answer?
babunello [35]

Answer:

Image B shows a reflection.

6 0
3 years ago
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If f(x)=|2x-4| find f(-7)
Yuri [45]

Answer:

18

Step-by-step explanation:

sub in x = -7 into the equation

f(-7) = |-14-4| = |-18| = 18

4 0
1 year ago
Simplity:<br> 17 (-12 + 3)
Schach [20]

Answer:

\Huge\boxed{\mathsf{-153}}}

Step-by-step explanation:

\Large\boxed{\mathsf{LESSON: ORDER \quad OF \quad OPERATIONS}}}

\Large\boxed{\mathsf{SUBJECT: MATH}}}

To use the order of operations stands for (Parenthesis, Exponents, Multiply, Divide, Add, and Subtract) from left to right.

First, do parenthesis.

17(-12+3)

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17(-9)

Then, multiply.

17*9=153

17(-9)=-153

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\Large\boxed{\mathsf{\Rightarrow -153}}

The correct answer is -153.

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7+8+10=25cm is the possibile perimeter of this

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