Weights of cars passing over Bridge part 3
1 answer:
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Answer:
A. Complete table below
B. Graph is attached below
C. y = 7x - 10
D. 60 pounds.
Step-by-step explanation:
We are given that, Bayer would grow at an average rate of 7 pounds per month.
So, in order to complete the table, <em>we will add 7 to the weights column</em>.
Part A: Thus, we get the following table.
Age, in months 2, 3, 4, 5, 6, 7, 8
Weight, in pounds 4, 11, 18, 25, 32, 39, 46.
Part B: Since, we have the ordered pairs (x,y) given by,
(2,4), (3,11), (4,18), (5,25), (6,32), (7,39) and (8,46).
The graph is shown below.
Part C: Taking any two pairs say (2,4) and (3,11).
We get the slope is, i.e. slope is 7.
Then, y = mx + b gives, 4 = 7×2 + b i.e. b = 4-14 i.e. b = -10.
Hence, the linear model is given by 'y=7x-10', where x is the age(in months) and y is the weight(in pounds).
Part D: Now, we want to find the weight when Bayer is one year old.
Since, we have that, Bayer is already two months old.
So, we need to find weight when Bayer is 10 months old.
i.e. y=7x-10 ⇒ y = 7×10-10 ⇒ y = 70-10 ⇒ y=60
Hence, Bayer will be 60 pounds when he is one year orld.
