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Montano1993 [528]
3 years ago
11

Mrs riddle has $543.73 in her bank account? She writes a check for $840.00. By how much has she overdrawn her account?

Mathematics
1 answer:
Alexxandr [17]3 years ago
3 0

Answer: im only in middle school so this might be wrong but...

-296.27

Step-by-step explanation:

because

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Leah loves chicken wings and is comparing the deals at three different restaurants. Buffalo Bills has 888 wings for \$7$7dollar
ella [17]

Cost of chicken wings at Buffalo Bills = 8 wings for $7

Cost of 1 wing at Buffalo Bills = \frac{7}{8} =0.875

Cost of chicken wings at Buffalo Mild Wings = 12 wings for $10

Cost of 1 wing at Buffalo Mild Wings = \frac{10}{12}= 0.833

Cost of chicken wings at Wingers = 20 wings at $17

Cost of 1 wing at Wingers = \frac{17}{20}= 0.850

Hence, comparing all the three costs per wing, we can see that Buffalo Mild Wings is serving chicken wings at lowest price of $0.833 per wing.

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Answer:

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3 years ago
It takes Flora 3 hours to knit a pair of socks and 7 hours to knit a pair of gloves. If she spent 100 hours knitting a total of
gavmur [86]
3 pairs of socks and 13 pairs of gloves
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Inverse laplace of [(1/s^2)-(48/s^5)]
Katen [24]
**Refresh page if you see [ tex ]**

I am not familiar with Laplace transforms, so my explanation probably won't help, but given that for two Laplace transform F(s) and G(s), then \mathcal{L}^{-1}\{aF(s)+bG(s)\} = a\mathcal{L}^{-1}\{F(s)\}+b\mathcal{L}^{-1}\{G(s)\}

Given that \dfrac{1}{s^2} = \dfrac{1!}{s^2} and -\dfrac{48}{s^5} = -2\cdot\dfrac{4!}{s^5}

So you have \mathcal{L}^{-1}\left\{\dfrac{1}{s^2} - 2\cdot\dfrac{4!}{s^5}\right\} = \mathcal{L}^{-1}\left\{\dfrac{1}{s^2}\right\} - 2\mathcal{L}^{-1}\left\{\dfrac{4!}{s^5}\right\}

From Table of Laplace Transform, you have \mathcal{L}\{t^n\} = \dfrac{n!}{s^{n+1}} and hence \mathcal{L}^{-1}\left\{\dfrac{n!}{s^{n+1}}\right\} = t^n

So you have \mathcal{L}^{-1}\left\{\dfrac{1}{s^2}\right\} - 2\mathcal{L}^{-1}\left\{\dfrac{4!}{s^5}\right\} = \boxed{t-2t^4}.

Hope this helps...
7 0
3 years ago
-10x-6y=0 -4x -6y=54 find the solution of this system of equations
ad-work [718]

You can see that the term -6y appears in both equations. In this cases, we can leverage this peculiarity and subtract the two equations to get rid of the repeated term. So, if we subtract the first equation from the second, we have

(-4x -6y) - (-10x-6y) = 54-0 \iff 6x = 54 \iff x = 9

Now that we know the value of x, we can substitute in any of the equation to deduce the value of y: if we use the first equation, for example, we have

-10x-6y=0 \iff -10\cdot 9 - 6y = 0 \iff -90-6y=0 \iff 6y = -90 \iff y = -15

7 0
3 years ago
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