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Answer:100mm
Step-by-step explanation:
Answer:
638
Step-by-step explanation:
1. Isolate the variable 881 = k - (-243)
-243 -243
2. combine like terms 881 - 243 = k
3. answer 638
Given:
The equation is:

It cuts the x-axis and y- axis at the point A and B respectively.
The area of ∆AOB =12 sq.units.
To find:
The value of <em>k</em>.
Solution:
We have,

Substituting
to find the y-intercept.




Substituting
to find the x-intercept.



Area of a triangle is:

The height of the ∆AOB is
because distance cannot be negative and the base of the ∆AOB is
. So, the area of the ∆AOB is:


It is given that, the area of ∆AOB = 12 sq.units.




Therefore, the value of k is either 24 or -24.
Part ÷ Whole = Percent
63 ÷ 70 = 0.9
0.9 x 100 = 90
<em>63 is 90% of 70
</em>Hope this helps,
<em>♥</em><em>A.W.E.<u>S.W.A.N.</u></em><em>♥</em>