All categories

4 years ago

Determine whether the sequence converges or diverges. If it converges, give the limit.

1 answer:

azamat4 years ago

4 0

The term to term rule is multiplying by 4 and if we continue doing this, we will move towards very large positive numbers.

This sequence, therefore, diverges to infinity

You might be interested in

The following diagram shows the side view of a roof and attic space of a newly constructed

CaHeK987 [17]

Answer:

A 20

Step-by-step explanation:

yeah-ya....... right?

6 0

3 years ago

Can an area of a polygon be zero? true or false

Nata [24]

False. If the area is 0 that means there is nothing there, therefore the area of a polygon cannot be zero.

4 0

3 years ago

Read 2 more answers

25 pealties decreased by 35% is how many penalties

Harman [31]

16.25 penalties.
35% of 25 is 8.75.
25-8.75=16.25

5 0

4 years ago

Read 2 more answers

Slope of (9,2) and (6,-2)

Dahasolnce [82]

Answer:

m= 4/3

Step-by-step explanation:

4 0

3 years ago

1+secA/sec A = sin^2 A / 1-cos A

Fofino [41]

Answer: see proof below

Step-by-step explanation:

$\dfrac{1+\sec A}{\sec A}=\dfrac{\sin^2 A}{1-\cos A}$

Use the following Identities:

sec Ф = 1/cos Ф

cos² Ф + sin² Ф = 1

Proof LHS → RHS

$\text{LHS:}\qquad \qquad \dfrac{1+\sec A}{\sec A}$

$\text{Identity:}\qquad \qquad \dfrac{1+\frac{1}{\cos A}}{\frac{1}{\cos A}}$

$\text{Simplify:}\qquad \qquad \dfrac{\frac{\cos A+1}{\cos A}}{\frac{1}{\cos A}}\\\\\\.\qquad \qquad \qquad =\dfrac{1+\cos A}{1}$

$\text{Multiply:}\qquad \qquad \dfrac{1+\cos A}{1}\cdot \bigg(\dfrac{1-\cos A}{1-\cos A}\bigg)\\\\\\.\qquad \qquad \qquad =\dfrac{1-\cos^2 A}{1-\cos A}$

$\text{Identity:}\qquad \qquad \dfrac{\sin^2 A}{1-\cos A}$

$\text{LHS = RHS:}\quad \dfrac{\sin^2 A}{1-\cos A}=\dfrac{\sin^2 A}{1-\cos A}\quad \checkmark$

3 0

4 years ago