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Minchanka [31]
3 years ago
15

Expand and simplify (2x+3)(x-3)

Mathematics
2 answers:
8090 [49]3 years ago
6 0
2x^2-3x+3x-9
Answer: 2x^2-9
timofeeve [1]3 years ago
5 0
2x^2-6x+3x-9

FINAL ANSWER:
2x^2-3x-9
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Can you write a real world problem that uses Pythagorean theorem ?
elena-14-01-66 [18.8K]

1) Road Trip: Let’s say two friends are meeting at a playground. Mary is already at the park but her friend Bob needs to get there taking the shortest path possible. Bob has two way he can go - he can follow the roads getting to the park - first heading south 3 miles, then heading west four miles. The total distance covered following the roads will be 7 miles. The other way he can get there is by cutting through some open fields and walk directly to the park. If we apply Pythagoras's theorem to calculate the distance you will get:

(3)<span>2 </span>+ (4)2 =

9 + 16 = C2

√25 = C

5 Miles. = C

Walking through the field will be 2 miles shorter than walking along the roads. .

2) Painting on a Wall: Painters use ladders to paint on high buildings and often use the help of Pythagoras' theorem to complete their work. The painter needs to determine how tall a ladder needs to be in order to safely place the base away from the wall so it won't tip over. In this case the ladder itself will be the hypotenuse. Take for example a painter who has to paint a wall which is about 3 m high. The painter has to put the base of the ladder 2 m away from the wall to ensure it won't tip. What will be the length of the ladder required by the painter to complete his work? You can calculate it using Pythagoras' theorem:

(5)<span>2 </span>+ (2)2 =

25 + 4 = C2

√100 = C

5.3 m. = C

Thus, the painter will need a ladder about 5 meters high.

3) Buying a Suitcase: Mr. Harry wants to purchase a suitcase. The shopkeeper tells Mr. Harry that he has a 30 inch of suitcase available at present and the height of the suitcase is 18 inches. Calculate the actual length of the suitcase for Mr. Harry using Pythagoras' theorem. It is calculated this way:

(18)<span>2 </span>+ (b)2 = (30)2

324 + b2 = 900

B2 = 900 – 324

b= √576

= 24 inches

6 0
3 years ago
How many ways can 100 be written as the sum of distinct integers from the set {1, 2,..., 15}?
konstantin123 [22]

Answer:

48 ways

Step-by-step explanation:

Let me take a guess

S₁_₁₅ = (1+15)*7 + 8 = 120

There are 48 combinations of distinct digits from 1 to 15 to make 20

120-20=100

So every 20 has a corresponding 100

I wish I got it right, otherwise report it.

4 0
2 years ago
Use the marked parallel lines to find the value of y in the diagram below (1 point)
Inessa [10]
2x + 5 = 3x - 45                    [alternate interior angles]
3x - 2x = 5 + 45
x = 50

4y - 1 + 2x + 5 = 180                [supplementaly angles]
4y + 2(50) + 4 = 180
4y + 100 = 176
4y = 76
y = 19
7 0
3 years ago
A central angle Theta of a circle with a radius of 16 inches intercepts an arc of 19.36 inches, find theta
rosijanka [135]
The length of the arc =R × theta
theta =the length of the arc /R
theta =16/19.36
that's what i know
7 0
3 years ago
Read 2 more answers
Make a box and whiskers plot of the data. average temperature in Pittsburgh in June 79,70,73,84,83,88,75,72,76,68,68,79,84,74,75
aliya0001 [1]
The box-and-whisker plot is attached.

We first order the data from least to greatest:
67,68,68,69,70,72,73,74,75,75,76,78,79,79,80,83,84,85,85,88

Now we find the median.  Since there are 20 data values, the median is between 75 and 76:
(75+76)/2 = 151/2 = 75.5

Now we find the Lower Quartile (LQ).  We do this by finding the median of the lower half of data (from the median down).  There are 10 values here; the median is between 70 and 72:
(70+72)/2 = 142/2 = 71

Find the Upper Quartile (UQ).  Do this by finding the median of the upper half of data (from the median up).  There are 10 values here; the median is between 80 and 83:
(80+83)/2 = 163/2 = 81.5

The middle bar of the box is over the median.  The left hand side of the box is over LQ, and the right hand side of the box is over UQ.  Now we draw a whisker from the box to the highest value, 88, and from the box to the lowest value, 67.

7 0
3 years ago
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