The formula for finding the perimeter of a quadrilateral is Length + Length + Width + Width.
<h3>What is Perimeter?</h3>
- A perimeter is the path that surrounds a certain shape. To calculate the path that surrounds a quadrilateral, we need to get the sum of its four sides, both lengths and widths, lengths being the longest sides and the widths being the shortest.
- The formula used for calculating perimeter is Perimeter = Length + Length + Width + Width.
- For instance, to calculate the perimeter of a parallelogram with a side of 5 cm and one of 3 cm, we insert the numbers in their corresponding spot in the formula as such: Perimeter=5+5+3+3=16 cm or since parallelograms have 2 sets of 2 equal sides, we can use this formula Perimeter=(5×2)+(3×2)=10+6=16 cm.
- For a square on the other hand, we only need to know the length of one side because it has 4 equal sides.
Therefore, the formula for finding the perimeter of a quadrilateral is Length + Length + Width + Width.
Learn more about quadrilateral here:
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Answer: It depends on which variable you're solving for.
Step-by-step explanation:
Solving for b: b=7/8mx + -1/8xy
Solving for m: m=xy+8b
______
7x
Solving for x: x=-8b
___
-7m+y
Solving for y: y=7mx-8b
______
x
I do not the question. Please explain
The derivative of 
at a point 
in the direction of a vector 
is
We have
and
Then the derivative at 
in the direction of 
is
Answer:
see below
Step-by-step explanation:
some of your answers that you currently have are wrong, I'll note those mistakes below
- when factoring (ie 5x+15) only factor out things that can divide both numbers into a whole number ratio
5x+15 = 5(x+3), not (x+3)(x+5)
ie 
we see that 10x can divide the numerator in a whole number ratio
= 10x(x+2), not (x+2)(x+10)
second mistake: the first binomial expansion is incorrect.
you have the expansion formula right, but you added terms wrong, go look at it again
3. x^2+3x+2/ x^2+5x+6
(x+1)(x+2)/(x+3)(x+2)
(x+1)/(x+3)
4. (x^2+6x+8)/(x^2-16)
(x+4)(x+2)/(x+4)(x-4)
(x+2)/(x-4)
5. we can't simplify that any more, x and y are different variables so therefore we cannot cross out stuff on numerator and denominator
6. (x^4y^6)^2
(x^4y^6)(x^4y^6) = 
remember that (x^a)(x^b) = x^(a+b)
or remember that (x^a)^b = x^ab
