What is the slope of the line tangent to the curve y+2=x22−2siny at the point(2,0)
1 answer:
Answer:
Step-by-step explanation:
hello :
y+2=x²−2siny
calculate y' : y' = 2x -2y'cosy
when x= 2 and y=0 ( at the point(2,0)
) y' is the slope :
y' = 2(2)-2y'cos0 but cos0 =1
y' = 4 -2y'
3y' =4
so : y' = 4/3
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