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3 years ago

What is the slope of the line tangent to the curve y+2=x22−2siny at the point(2,0)

Mathematics

1 answer:

Kobotan [32]3 years ago

3 0

Answer:

Step-by-step explanation:

hello :

y+2=x²−2siny

calculate y' : y' = 2x -2y'cosy

when x= 2 and y=0 ( at the point(2,0) ) y' is the slope :

y' = 2(2)-2y'cos0 but cos0 =1

y' = 4 -2y'

3y' =4

so : y' = 4/3

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Determine the equations of the vertical and horizontal asymptotes if any for h(x)=(x+1)^2/x^2-1

shepuryov [24]

ANSWER

Vertical asymptote:

x=1

Horizontal asymptote:

y=1

EXPLANATION

The given rational function is

$h(x) = \frac{ {(x + 1)}^{2} }{ {x}^{2} - 1 }$

$h(x) = \frac{ {(x + 1)}^{2} }{ ({x} - 1)(x + 1)}$

$h(x) = \frac{ (x + 1)(x + 1) }{ ({x} - 1)(x + 1)}$

$h(x) = \frac{ x + 1}{ {x} - 1}$

The vertical asymptote occurs at

${x} - 1 = 0$

$x = 1$

The vertical asymptotes is x=1

The degree of the numerator is the same as the degree of the denominator.

The horizontal asymptote of such rational function is found by expressing the coefficient of the leading term in the numerator over that of the denominator.

$y = \frac{1}{1}$

y=1

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5u^2 + 6 = -13u please help

Komok [63]

Answer:

u = -2, -3/5

General Formulas and Concepts:

Algebra I

Standard Form: ax² + bx + c = 0
Factoring
Finding roots

Step-by-step explanation:

Step 1: Define equation

5u² + 6 = -13u

Step 2: Solve for u

Rewrite: 5u² + 13u + 6 = 0
Factor: (u + 2)(5u + 3) = 0
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Step-by-step explanation:

Explanation is in the attachment

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