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zavuch27 [327]
3 years ago
15

If the mean of symmetrical distribution is 28, which of these values could be the median of the distribution.

Mathematics
1 answer:
lina2011 [118]3 years ago
6 0
If a distribution is symmetric, its mean is the same as its median, so the median would also be 28.
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Its 5/9 divide by five<span />
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What is the value of x? There is isosceles triangle. The measure of angle which is between two congruent sides is (6x+10⁰). The
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<h3><u>Answer</u><u>:</u><u>-</u></h3>

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<h3><u>step-by</u><u>-</u><u>step</u><u> </u><u>Explanation</u><u>:</u><u>-</u></h3>

{\boxed{\quad\:\mapsto\rm Firstly\:Let's\:understand\:the\:concept:-}}

<h3 />

This is a isosceles triangle. As it is a triangle we can apply sum theory. we have to take the sum of given unknown polynomials as 180° .Then by solving it we can find the value of x.

<h3><u>Solution</u><u>:</u><u>-</u></h3>

Given angles

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According to sum theory

{\boxed{\sf The \:sum\:of\:angles=180°}}

  • Substitute the values

\qquad \quad{:}\longmapsto\tt (6x+10)+(x+17)+(4x-34)=180

  • Remove brackets

\qquad \quad{:}\longmapsto\tt 6x+10+x+17+4x-34=180

  • Together like polynomials and constants

\qquad \quad{:}\longmapsto\tt 6x+x+4x+10+17-34=180

\qquad \quad{:}\longmapsto\tt 11x-7=180

  • Interchange sides

\qquad \quad{:}\longmapsto\tt 11x=180+7

\qquad \quad{:}\longmapsto\tt 11x=187

\qquad \quad{:}\longmapsto\tt x=\cancel{\dfrac{187}{11}}

  • Simplify

\qquad \quad{:}\longmapsto\tt x=17

\therefore\sf The \:value\:of\:x\;is\:17.

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Some friends shared 2 bags of chips. If each person got 2/3 of a bag of chips, how many friends were there?
quester [9]

Answer:

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Step-by-step explanation:

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