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kap26 [50]
3 years ago
6

Please help with this question

Mathematics
1 answer:
NemiM [27]3 years ago
4 0
Use the equation a^2 + b^2 = c^2.

225 + 1296 = c^2
1596 = c^2
Square root both

39 = c

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Which values are in the solution set of the compound inequality: 4(x+3)≤0 or 14x+1>3
ludmilkaskok [199]

Answer: 69

Step-by-step explanation: The hypotenuse of the atom and it’s vastly large core equals the square root of 420 divides by 5.4 which equals 69.

3 0
3 years ago
For the inverse variation equation p = StartFraction 8 Over V EndFraction, what is the value of V when p = one-half?
likoan [24]

Answer:

V=16

Step-by-step explanation:

We are given that an inverse variation

p=\frac{8}{V}

We have to find the value of V when p=1/2

To find the value of V we will substitute the value of p

Substitute the value of p

Then, we get

\frac{1}{2}=\frac{8}{V}

\frac{V}{2}=8

Using multiplication property of equality

V=8\times 2

Using multiplication property of equality

V=16

Hence, the value of V=16

3 0
3 years ago
$20 haircut ; 10% tip
Trava [24]

Answer:

22 dollars

Step-by-step explanation:

10% of $20= 2

20+2=$22

3 0
3 years ago
Math answer homework​
stiv31 [10]

Answer:

2:15 p.m.

Step-by-step explanation:

Starting time                1:40 p.m.

Time on subway       <u>+0:17 </u>

Time off subway          1:57 p.m.

Time walking            <u>+0:18 </u>

Time at apartment       1:75

When the minutes are more than 60, you subtract 60 from the minutes and add 1 to the hours.

 1   :75

+1<u> - :60 </u>

  2 :15 p.m.

Daniel arrived at the apartment at 2:15 p.m.

8 0
3 years ago
Jerry indicated that after tossing a penny 30 times, the relative frequency of heads was 0.47 (to the nearest hundredth). He ind
natali 33 [55]

Answer:

Incorrect.

Step-by-step explanation:

1 toss could not change the frequency by such a large margin 0.47 ---> 0.55.

The number of heads obtained in 30 tosses = 30 * 0.47 =  14.

So if the next toss came up heads the relative frequency of heads would be

15/31 = 0.48.

4 0
3 years ago
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