4/7 - x = 6/35
You're trying to get x by itself, so you have to subtract 4/7 from both sides.
-x = 6/35 - 4/7
You need both of the fractions to the right of the equal sign to have the same denominator so that we could simplify them, so multiply 5/5 to -4/7.
-4 /7 × 5/5 = -20/35
So, our new equation is :
-x = 6/35 - 20/35
Simplify.
-x = -14/35
Divide both sides by -1.
x = 14/35
Divide by 7.
x = 2/5
~Hope I helped!~
Answer:
B. 7√3
Step-by-step explanation:
30-60-90 triangles have special side proportions that would be very beneficial to memorize because I guarantee you will use it in the future.
Please see the attached image.
The answer is 7*√3=7√3
Answer:
Lo siento, solo necesitaba los puntos
Step-by-step explanation:
Lo siento, solo necesitaba los puntos
Lo siento, solo necesitaba los puntos
Lo siento, solo necesitaba los puntosvv
Lo siento, solo necesitaba los puntos
Lo siento, solo necesitaba los puntosvvv
Complete Question
A milling process has an upper specification of 1.68 millimeters and a lower specification of 1.52 millimeters. A sample of parts had a mean of 1.6 millimeters with a standard deviation of 0.03 millimeters. what standard deviation will be needed to achieve a process capability index f 2.0?
Answer:
The value required is
Step-by-step explanation:
From the question we are told that
The upper specification is 
The lower specification is
The sample mean is
The standard deviation is 
Generally the capability index in mathematically represented as
![Cpk = min[ \frac{USL - \mu }{ 3 * \sigma } , \frac{\mu - LSL }{ 3 * \sigma } ]](https://tex.z-dn.net/?f=Cpk%20%20%3D%20%20min%5B%20%5Cfrac%7BUSL%20-%20%20%5Cmu%20%7D%7B%203%20%2A%20%20%5Csigma%20%7D%20%20%2C%20%20%5Cfrac%7B%5Cmu%20-%20LSL%20%7D%7B%203%20%2A%20%20%5Csigma%20%7D%20%5D)
Now what min means is that the value of CPk is the minimum between the value is the bracket
substituting value given in the question
![Cpk = min[ \frac{1.68 - 1.6 }{ 3 * 0.03 } , \frac{1.60 - 1.52 }{ 3 * 0.03} ]](https://tex.z-dn.net/?f=Cpk%20%20%3D%20%20min%5B%20%5Cfrac%7B1.68%20-%20%201.6%20%7D%7B%203%20%2A%20%200.03%20%7D%20%20%2C%20%20%5Cfrac%7B1.60%20-%20%201.52%20%7D%7B%203%20%2A%20%200.03%7D%20%5D)
=> ![Cpk = min[ 0.88 , 0.88 ]](https://tex.z-dn.net/?f=Cpk%20%20%3D%20%20min%5B%200.88%20%2C%200.88%20%20%5D)
So

Now from the question we are asked to evaluated the value of standard deviation that will produce a capability index of 2
Now let assuming that

So

=> 
=> 
So

=> 
Hence
![Cpk = min[ 2, 2 ]](https://tex.z-dn.net/?f=Cpk%20%20%3D%20%20min%5B%202%2C%202%20%5D)
So

So
is the value of standard deviation required
Volume of Cylinder = πr²h
Radius r = 14.5 feet
Volume, V = 4950 cubic feet
4950 = π*14.5²*h
π*14.5²*h = 4950
h = 4950 / (π*14.5²) Use your calculator with π function
h = 7.494
Therefore height ≈ 7.50 feet to the nearest tenth of a foot.