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AleksandrR [38]
3 years ago
10

The yearly cost in dollars, y, for a member at a video game arcade based on total game tokens purchased, x, is y =x + 60.

Mathematics
2 answers:
lara31 [8.8K]3 years ago
8 0
The yearly cost for a non-member would be : y = 0.20x
DIA [1.3K]3 years ago
4 0
Y=1/5x is your answer
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Solve in one variable<br> 2/3x + 5 = 3/2x
Montano1993 [528]
First, we group together the terms with variables in one side by subtracting 3/2 x and 5 from both sides of the equation.
                   (2/3)x - (3/2)x + 5 - 5 = (3/2)x - (3/2)x - 5
                         (-5/6)x = -5
The value of x from the equation is 6. 
5 0
3 years ago
Help Plz
serg [7]
Hey!
Let p = cost of a pen 
<span>Let n = cost of a notebook </span>

<span>The info in the question leads to two equations: </span>

<span>1) 2p + 3n = 5.55 </span>
<span>2) p + 2n = 3.50 </span>

<span>Multiply equation 2) by 2 to get the new system of equations </span>

<span>1a) 2p + 3n = 5.55 </span>
<span>2a) 2p + 4n = 7.00 </span>

<span>Subtract equation 1a) from equation 2a) to get </span>

<span>n = 1.45 ...................... that's the cost of one notebook </span>

<span>~~~~~~~~ </span>
<span>To check, you could go on to figure out p, which turns out to be 0.60 . Put in those values of n and p into the original equations to verify.</span>
Hope this helps! ~Nadia~
6 0
4 years ago
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How do you solve <br> 5q-7=2/3
erastova [34]
5q-7=\frac{2}{3}\ \ \ \ \ \ |add\ 7\ to\ both\ sides\\\\5q=7\frac{2}{3}\\\\5q=\frac{23}{3}\ \ \ \ \ \ |divide\ both\ sides\ by\ 5\\\\\boxed{q=\frac{23}{15}}
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3 years ago
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Yelena is able to run 8 miles.She trains so that each week she is able to run 2 more miles than she could the week before. How m
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Answer:5m



Step-by-step explanation:


8 0
4 years ago
I WILL MARK BRAINLIEST!!!!! NEED HELP!
s344n2d4d5 [400]
Since variables x and y are in direct proportion,

Y = 12.5/25 x 40
Y = 0.5 x 40
Y = 20.
6 0
3 years ago
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