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Marta_Voda [28]
3 years ago
6

What is the simplified form of the following expression?

Mathematics
1 answer:
ziro4ka [17]3 years ago
7 0

For this case we must simplify the following expression:7 (\sqrt [3] {2x}) - 3 (\sqrt [3] {16x}) - 3 (\sqrt [3] {8x})

We rewrite:

16x = 2 ^ 3 * 2x\\8x = 2 ^ 3 * x

We rewrite the expression:

7 (\sqrt [3] {2x}) - 3 (\sqrt [3] {2 ^ 3 * 2x}) - 3 (\sqrt [3] {2 ^ 3 * x}) =

By definition of properties of powers and roots we have:

\sqrt [n] {a ^ m} = a ^ {\frac {m} {n}}

Then, taking the terms of the radical:

7 (\sqrt [3] {2x}) - 3 (2 \sqrt [3] {2x}) - 3 (2 \sqrt [3] {x}) =\\7 \sqrt [3] {2x} -6 \sqrt [3] {2x} -6 \sqrt [3] {x} =

We add similar terms:

\sqrt [3] {2x} -6 \sqrt [3] {x}

Answer:

Option C

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You are at a restaurant and the check comes to a total of $79. If you want to leave a
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Answer:

$92.43

Step-by-step explanation:

Original value of money paid is $79

Tip is 17% of $79 = $13.43

Total is the original value + the tip

79 x 0.17(this is because 17% is the same as 17/100 If you turn this to a decimal you get 0.17) = $13.43

Total = $13.43 + $79

$92.43 the 43 cents are whole so there is no need to round off.

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3 years ago
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Step-by-step explanation:

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Create a sequence with five terms based on the given information. a. A arithmetic sequence with a third term of 8 and a constant
kolezko [41]

Part a .

A arithmetic sequence with a third term of 8 and a common difference of 5 .

To find the first five therms, since the common difference is 5, so we add 5 to get the fourth term and add 5 to fourth term to get the fifth term .

And for first two terms, we will subtract 5 from 8 to get the second term and subtract 5 from the second term to get the first term. And we will get

8-5-5,8-5,8, 8+5+5 = -2 ,3,8,13,18

Part b:A geometric sequence with a fifth term of 1/3 and constant ratio of 1/3.

TO find the first five terms, since the constant ratio of 1/3, so we multiply 1/3 to third term to get fourth term, and multiply fourth term by 1/3 to get fifth term .

And to get the first two terms, we will divide third term by 1/3, to get the second term and divide the second term by 1/3 to get the first term, that is

3,1,\frac{1}{3}, \frac{1}{9},\frac{1}{27}



6 0
3 years ago
Solve:<br><br> If Sally can walk 1/3 of a mile in 1/4 of an hour. How far will she walk 2 1/2 hours?
Daniel [21]
The answer is 3 and 1/3 miles
8 0
3 years ago
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For the level 3 course, exam hours cost twice as much as workshop hours, workshop hours cost twice as much as lecture hours. How
natulia [17]
<h2>Answer</h2>

Cost of lectures = $7.33 per hour

<h2>Explanation</h2>

Let e the cost of the exam hours

Let w be the cost of the workshop hours

Let l be the cost of the lecture hours.

We know from our problem that exam hours cost twice as much as workshop, so:

e=2w equation (1)

We also know that workshop hours cost twice as much as lecture hours, so:

w=2l equation (2)

Finally, we also know that 3hr exams 24hr workshops  and 12hr lectures cost $528, so:

3e+24w+12l=528 equation (1)

Now, lets find the value of l:

Step 1.  Solve for l in equation (3)

3e+24w+12l=528

12l=528-3e-24w equation (4)

Step 2. Replace equation (1) in equation (4) and simplify

12l=528-3e-24w

12l=528-3(2w)-24w

12l=528-6w-24w

12l=528-30w equation (5)

Step 3. Replace equation (2) in equation (5) and solve for l

12l=528-30w

12l=528-30(2l)

12l=528-60l

72l=528

l=\frac{528}{72}

l=\frac{22}{3}

l=7.33

Cost of lectures  = $7.33 per hour



3 0
3 years ago
Read 2 more answers
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