Answer:
no noooooooooooooooooooooooooooooooooooooooooooooooooooooo
Step-by-step explanation:
You want to find the area left over after the pool is built, so subtract the area of the pool from the area of the yard.
Area of Yard= Base x Height = 14x*19x = 266x^2
Area of Circle= Pi x Radius^2 = (6x)^2*pi = 36x^2*pi
Now subtract the two areas:
266x^2-(36^2*pi)
266x^2-36x^2*pi
Take 2x^2 as a common factor:
2x^2(133-18pi)
D: <span>2x^2(133-18pi)
Hope this helps :)</span>
-5= -5x-10
Plus 10 from both sides
5=-5x
X = -1
The answer is 1/3 of 12 its just easy math for me
Answer:
z = 21 ; y= 16
Step-by-step explanation:
first of all we have to isolate a variable.
In second expression we can obtain:
3y = 2z+6
y = 2/3 z + 2
now we have to substitute this value in the first equation and solve it
8(2/3z+2)-5z = 23
16/3z + 16 -5z = 23
16z +48 - 15z = 69
z = 21
now we have to substitute z in the second equation:
y = 2/3 (21) +2
y = 14+ 2 = 16
y = 16
