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sveta [45]
3 years ago
5

Alexis G. has a cell phone plan that charges $0.05 per minute plus a monthly fee of $25.00. She budgets $35.50 per month for tot

al cell phone expenses without taxes. What is the maximum number of minutes Alexis could use her phone each month in order to stay within her budget?
NEED ANSWER IMIDIETLY!!!!!!!!!!!!
Mathematics
1 answer:
jeyben [28]3 years ago
6 0
The Maximum amount of minutes she could use would be 210

Formula:
0.05x + 25 <= 35.50
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What is the regular price of a taco before the discount​
Amanda [17]

Answer:

60

Step-by-step explanation:

100 x 0.4 = 40 and that is the discount so you subtract that off the price so 100 - 40 = 60

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Appreciate all the help :)<br> Which matrix multiplication is defined?
zubka84 [21]

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c. BC

Step-by-step explanation:

It is the possible one

8 0
3 years ago
The blue lake trail is 11 3/8 miles long. Gemma has hiked 2 1/3 miles each hour for 3 hours. How far is she from the end of the
sergeinik [125]

Answer:

4\frac{3}{8}miles

Step-by-step explanation:

Given that Gemma has hiked 2 1/3 mile each hour for a total of 3 hours, you can multiply her rate by her time to find the total distance:

d = rt or d = 2 1/3(3)

2\frac{1}{3}=\frac{7}{3}

Multiply: \frac{7}{3}*\frac{3}{1}=7miles

Now, that the total length of the trail, 11 3/8 miles, and subtract the distance that Gemma has gone already:

11 3/8 - 7 = 4\frac{3}{8}miles

4 0
3 years ago
Find two positive numbers whose difference is 30 and whose product is 2584.
kvasek [131]

Answer:

38 and 68.

Step-by-step explanation:

Let x be the smaller one of the two number.

x must be a positive integer. The other number would be (x + 30).

The question states that the product of the two numbers is 2584. In other words:

x\, (x + 30) = 2584.

Rearrange this equation and solve for x:

x^{2} + 30\, x - 2584 = 0.

The first root of this quadratic equation would be:

\begin{aligned}x_{1} &= \frac{(-30) + \sqrt{30^{2} - 4 \times (-2584)}}{2} \\ &= \frac{(-30) + \sqrt{900 + 10336}}{2} \\ &= \frac{(-30) + \sqrt{11236}}{2} \\ &= \frac{(-30)}{2} + \sqrt{\frac{11236}{2^{2}}} \\ &= (-15) + \sqrt{2809} \\ &= (-15) + 53 \\ &= 38 \end{aligned}.

Similarly, the second root of this quadratic equation would be:

\begin{aligned}x_{1} &= \frac{(-30) - \sqrt{30^{2} - 4 \times (-2584)}}{2} \\ &= (-15) - 53 \\ &= -68\end{aligned}.

Since the question requires that both numbers should be positive, x > 0. Therefore, only x = 38 is valid.

Hence, the two numbers would be 38 and (38 + 30), which is 68.

6 0
3 years ago
Read 2 more answers
Can someone help me with this Im not sure if My answer is correct
sergeinik [125]

Answer:

y = 2x - 3

Yes, your answer is correct.

Step-by-step explanation:

First, find the slope of the two points by using the slope formula:

        y2 - y1

m = -------------

        x2 - x1

         13 - 5

m = -------------

          8 - 4

         8

m = ------- = 2

         4

To find the y-intercept, plug in values into the slope-intercept formula:

y = mx + b

Where m = slope and b= y-intercept. Use any one of the points. I'll be using (4,5):

5 = (2) (4) + b

5 = 8 + b

-3 = b

b = -3

So, putting everything into the slope intercept formula:

y = 2x - 3

4 0
3 years ago
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