HELP 20 PTS!!! Which ordered pair in the form (x, y) is a solution of this equation? (x + 7)y = 10

Mathematics

1 answer:

Vlad [161]3 years ago

8 0

Answer:

x = 3 y = 1

Step-by-step explanation:

3 + 7 = 10

10 x 1 = 10

Have a great day and good luck :)

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S part of a statistic project, a math class weighed all the children who were willing to participate as shown below.

katovenus [111]

Answer:

18 children weighed less than 50 pounds.

Step-by-step explanation:

Ok, adding into the explanation what the heck this kind of a table is. The "stem" column is the tens place of each of the children's weights. The "leaf" is the ones digit of each of the children's weights. So in the row where the stem is 2, there were 2 kids weighing 23 and 25 pounds.

For your question, we have to add up how many students have a weight with a "stem" less than 5, because that's where 50 pounds starts.

8 + 2 + 5 + 3 = 18 children weighed less than 50 pounds.

6 0

2 years ago

The graph below shows the value of Edna's profits f(t), in dollars, after t months:

umka21 [38]

Since we know that the graph of our quadratic function has x-intercepts at (6,0) and (18,0), $x=6$ and $x=18$ are the zeroes of our quadratic. To find our quadratic we are going to factor each zero backwards and multiply them:
$x=6$
$x-6=0$
$x=18$
$x-18=0$

$(x-6)(x-18)=x^{2}-6x-18x+108$
$=x^{2}-24x+108$

Now that we have our quadratic function, we are going to use the average formula: $m= \frac{f(9)-f(3)}{9-3}$
$where$
$f(9)$ is the function evaluated at the <span>9th month
</span> $f(3)$ is the function evaluated at the 3rd month

$m= \frac{f(9)-f(3)}{9-3}$
$m= \frac{[9^{2}-24(9)+108]-[3^{2}-24(3)+108]}{9-3}$
$m= \frac{-27-45}{6}$
$m= \frac{-72}{6}$
$m=-12$

We can conclude that the closest approximate average rate of change for Edna's profits from the 3rd month to the 9th month is: <span>B. −11.63 dollars per month.</span>