Question

If 3a+4a=14, and b+6b=21, then 7(a+b) = Help and show work!

Answer 1

Hello!

You have to find what a and b are

3a + 4a = 14
b + 6b = 21

Lets do a first

3a + 4a = 14

Combine like terms

7a = 14

Divide both sides by 7

a = 2

Now lets do b

b + 6b = 21

Combine like terms

7b = 21

Divide both sides by 7

b = 3

Put a and b into the third equation

7( 2 + 3) = 

Do what is in parenthesis first

7(5) = 

Multiply

35

The answer is 35

Hope this helps!

Answer 2

3a+4a=14 well we are combining terms so 3a and 4a will be 7a=14. Now we have an equality so we isolate the variable to give a the answer of 2. Then for b+6b=21 we do the same and combine terms having 7b since the single b there will always be a 1. Then we isolate the variable Again getting 3 for a. Lastly for 7(a+b) you have to disturb a and b with 7 which means (7*2)+(7*3)=14+21=35