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Aleksandr-060686 [28]
3 years ago
8

Name two red lines in the diagram that appear to be perpendicular

Mathematics
1 answer:
Crank3 years ago
5 0
It would be B PQ and SR
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The charts show the effect of an interest rate adjustment on an adjustable-rate mortgage.
Tcecarenko [31]

Answer:

C. a higher monthly payment.

Step-by-step explanation:

<h3>Answer options:</h3>

Rate adjustment resulted in

<u>A. a lower interest rate. </u>

  • No, interest rate increased from 0.4 to 0.5 percent

<u>B. a higher principal. </u>

  • No, principal decreased from $200000 to $187000

<u>C. a higher monthly payment. </u>

  • Yes, monthly payment increased from $1059.85 to $1162.56

<u>D. a higher number of payments.</u>

  • No, number of payments remained as 336
3 0
3 years ago
Find the slope of the line y= -8/5x + 2
VikaD [51]

Step-by-step explanation:

Given

y = - 8 /5 x + 2

Comparing the given equation with y = mx + c

slope (m) = - 8/5

Hope it will help :)

7 0
3 years ago
6 times the number of waiters at a restaurant was 6 less than the number of
morpeh [17]

Answer:

12

Step-by-step explanation:

6x3-6=12

8 0
3 years ago
Read 2 more answers
PLS HELP WILL MARK YOU BRAINLIEST! NO FAKE ANSWERS!!<br> WHAT IS M∠1?
TEA [102]

Answer:

angle 1=135°

Step-by-step explanation:

to find the angle of 1 you should know angle 2, what is angle 2?

angle 45° and angle 1 are symetrical so they have the same value.

now that we know that angle 2 is equal to 45°

then what is angle 1

if the whole line has an angle of 180° and angle 45°.

so the equation will be :

45+x=180

flip the equation to find x:

180-45=x

180-45=x\\135=x\\x=the angle 1 which we found in the given equation is 135

check if my answer is correct is :

135+45=180\\180=180

my equation is correct

8 0
2 years ago
Read 2 more answers
R = sec(θ) − 2cos(θ), where -π/2 &lt; θ &lt; π/2
Alex

Answer:

  y = (x/(1-x))√(1-x²)

Step-by-step explanation:

The equation can be translated to rectangular coordinates by using the relationships between polar and rectangular coordinates:

  x = r·cos(θ)

  y = r·sin(θ)

  x² +y² = r²

__

  r = sec(θ) -2cos(θ)

  r·cos(θ) = 1 -2cos(θ)² . . . . . . . . multiply by cos(θ)

  r²·r·cos(θ) = r² -2r²·cos(θ)² . . . multiply by r²

  (x² +y²)x = x² +y² -2x² . . . . . . . substitute rectangular relations

  x²(x +1) = y²(1 -x) . . . . . . . . . . . subtract xy²-x², factor

  y² = x²(1 +x)/(1 -x) = x²(1 -x²)/(1 -x)² . . . . multiply by (1-x)/(1-x)

  \boxed{y=\dfrac{x\sqrt{1-x^2}}{1-x}}

__

The attached graph shows the equivalence of the polar and rectangular forms.

4 0
2 years ago
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