The table shows the outputs, y, for different inputs, x:
1 answer:
You might be interested in
Answer:
The mass of the lamina is 1
Step-by-step explanation:
Let be a continuous density function of a lamina in the plane region D,then the mass of the lamina is given by:
.
From the question, the given density function is .
Again, the lamina occupies a rectangular region: D={(x, y) : 0 ≤ x ≤ 1, 0 ≤ y ≤ 1}.
The mass of the lamina can be found by evaluating the double integral:
.
Since D is a rectangular region, we can apply Fubini's Theorem to get:
.
Let the inner integral be: , then
.
The inner integral is evaluated using integration by parts.
Let , the partial derivative of u wrt y is
and
, integrating wrt y, we obtain
Recall the integration by parts formula:
This implies that:
We substitute the limits of integration and evaluate to get:
This implies that:
.
Or
.
We again apply integration by parts formula to get:
.
.
.
.
No unit is given, therefore the mass of the lamina is 1.