Answer: 103, 104, 105, and 106
Step-by-step explanation: This problem states that the sum of 4 consecutive integers is 418 and it asks us to find the integers.
First represent your 4 consecutive integers as follows.
X ⇒ first integer
X + 1 ⇒ second integer
X + 2 ⇒ third integer
X + 3 ⇒ fourth integer
Since their sum is 418, our equation reads
x + (x + 1) + (x + 2) + (x + 3) = 418.
Simplifying on the left side we get 4x + 6 = 418.
Now we can subtract 6 from both sides of the equation and we have
4x = 412.
Now just divide both sides by 4 and we find that <em>x = 103</em>.
Finally, make sure you list all your answers.
If <em>x</em> is 103, then <em>x </em>+ 1 is 104, <em>x</em> + 2 is 105, and <em>x</em> + 3 is 106
Therefore, our 3 consecutive integers are 103, 104, 105, and 106.
3+-4=-1
3-4=-1
-1=-1
so the answer is:
-1 = -1
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