Answer:
B. 26,606.63
Step-by-step explanation:
The area of Gateway National Recreation Area is about twenty-six thousand, six hundred six and sixty-three hundredths. Which shows this number in standard form? A. 26,606.3 B. 26,606.63
C. 26,660.63 D. 26,666.3
Solution
Break down and writing in numerals of twenty-six thousand, six hundred six and sixty-three hundredths.
Twenty six thousand = 26,000
Six hundred six = 606
Sixty - three hundredth = 0.63
Adding
26,000 + 606 + 0.63
We have
26,606.63
The correct answer is B
Answer:
Make sure you convert these numbers into one unit. Convert everything to yard. Just convert the feet and inches in yard since it's the biggest unit, and then add them together. You should get a fraction not a whole number.
The 5 and 10 min cross. 10
<span>The 5 min returns. 15 </span>
<span>The 20 and 25 min cross 40 </span>
<span>The 10 min comes back 50 </span>
<span>The 5 and 10 min cross again in60 Mins</span>
2.96 or 18.75 is the answer im leaning towards 2.96 though
Answer:
110.5348 minutes
Step-by-step explanation:
The difference from room temperature changes from 103 to 59 in 46 minutes, so that difference can be modeled by the exponential equation ...
Δt = 103×(59/103)^(t/46)
We want to find t for the temperature difference Δt = 91 -64 = 27.
27 = 103×(59/103)^(t/46)
27/103 = (59/103)^(t/46) . . . . . divide by 103
Taking logs gives the linear equation ...
log(27/103) = (t/46)log(59/103)
Multiplying by the inverse of the coefficient of t, we get ...
t = 46·log(27/103)/log(59/103) ≈ 46·(-0.58147346)/(-0.24198521)
≈ 110.5347
It will take about 110.5347 minutes for the turkey to cool to 91 °F internally.
_____
<em>Comment on 4 decimal places</em>
An answer correct to 4 decimal places (7 significant digits) is a pretty good indication that the problem was worked correctly. However, that level of precision in the timing makes little sense in this context. Most thermometers will take at least a few seconds to register the temperature to within a tenth of a degree or so. This problem is asking for an answer that is within 6 milliseconds and 30 micro-degrees. Neither of these is anywhere near realistic for a kitchen meat thermometer.
More realistic would be an answer to 4 <em>significant figures</em>, a tenth of a minute and a few hundredths of a degree.
(The rate of change at the time of interest is about -0.33 degrees per minute.)