Question

If the boy is 4' 9" tall and his shadow is 6 ft. and the shadow of the flagpole is 19 ft., determine the height of the flagpole (to the nearest tenth.

Answer 1

Height over shadow
H/S

9 in is 9/12=.75
So
Boys height /shadow. Flags height /shadow

4.75/6= X/19




Cross multiply
6x= 90.25
Divide by 6
X= 15.0

Answer 2

Answer:

The height of the flagpole(to the nearest tenth) is, 15.0 ft

Step-by-step explanation:

Proportion states that the two ratios or fractions are equal

As per the statement: If the boy is 4' 9" tall and his shadow is 6 ft. and shadow of the flagpole is 19 ft.

let the height of the flagpole be, h.

Use conversion:

1 ft = 12 inches.

Given: Height of the boy = $4'9" =4\frac{9}{12} = 4\frac{3}{4} = \frac{19}{4} ft$ , Shadow of the boy = 6 ft. and shadow of the flagpole=19 ft.

Using definition of proportion;

$\frac{Height of the boy}{Shadow of the boy} =\frac{Height of flagpole}{Shadow of flagpole}$

$\frac{\frac{19}{4}}{6}= \frac{h}{19}$

By cross multiply;

$\frac{19}{4} \times 19 =6h$

$\frac{361}{4} = 6h$

Divide both sides by 6 we get;

$\frac{361}{24} = h$

⇒ h = 15.0416667 ft.

therefore, the height of the flagpole(to the nearest tenth) is, 15.0 ft