find two consecutive even integers such that five times the smaller integer is ten more than three times the larger integer

Find the equation of the line that passes through the points (12,21) and (46,33). V.35r-162

AnnZ [28]

Answer:

the answer is Y=(6/17)X + (285/17)

Step-by-step explanation:

1. Identify the X and Y coordinate of each point.

for example, the first point could be (12,21), therefore X1 = 12 and Y1 = 21 and the second point is then (46,33), therefore X2 = 46 and Y2 = 33

2. to find the equation of the line it is necessary to find the slope.

knowing that the equiation of the slope is M = Y2-Y1/X2-X1 we replace

$m=\frac{33-21}{46-12}=\frac{12}{34}$ and then we simplify the result to $\frac{12}{34}$

3. Using the Point-slope equation which is Y-Y1=M(X-X1) we replace

$Y-33=\frac{6}{17}(X-46)$

$Y=\frac{6}{17}X-\frac{276}{17}+33$

$Y=\frac{6}{17}X+\frac{285}{17}$

7 0

3 years ago

Solve by the addition method

Sladkaya [172]

Answer is no solution I believe

7 0

3 years ago

Find the value of x, if angle x measures 102 degrees

Over [174]

The answer is B
Have a good day!

3 0

3 years ago

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Which inequality is represented by the graph? y≥35x−1.5 y≤35x−1.5 y<35x−1.5 y>35x−1.5

Setler79 [48]

Answer:

y > 0.6x - 1.5

Step-by-step Explanation:

We need two points, to get to the equation of the graph.

Since we've got the following equation for two points (x1, y1), (x2, y2):-

$\boxed{ \mathsf{ \red{y - y_{1} = \frac{y_{2} - y_{1}}{x_{2} - x_{1}} (x - x_{1}) }}}$

okay soo

I found two points that lie on this graph, not on the shaded region but yeah the dotted line which defines the graph.

one point is <u>(0, -1.5)</u> which lies on the y axis(the point where the dotted line touches the y axis)

other point is <u>(2.5, 0)</u> and this lies on the x axis

placing these points in the place of (x1, y1) and (x2, y2) in the above mentioned equation

$\mathsf{\implies y - ( - 1.5) = \frac{0 -( - 1.5)}{2.5 -0 } (x -0 )}$

you can take any one as (x1, y1) or (x2, y2).

so upon solving the above equation we get

$\mathsf{\implies (y + 1.5) = \frac{0 + 1.5}{2.5 } (x )}$

$\mathsf{\implies y + 1.5 = \frac{ 1.5}{2.5 } x }$

$\mathsf{\implies y + 1.5 = \frac{ \cancel{1.5}\:\:{}^3}{\cancel{2.5}\:\:{}^5 } x }$

$\mathsf{\implies y + 1.5 = \frac{ 3}{5 } x }$

multiplying both sides by 5

$\mathsf{5y + 7.5 = 3x}$

okay so this is the required equation of the dotted line

now we'll find the inequality

for this check whether the origin (0,0) lies under the shaded region or not

in this case it does

so

replacing x and y with 0

$\mathsf{\implies5(0) + 7.5 = 3(0)}$

$\mathsf{\implies0 + 7.5 = 0}$

this is absurd, 7.5 is not equal to 0 so we're gonna replace that equals sign with that of inequality

7.5 is greater than 0! so,

$\mathsf{\implies7.5 > 0}$

this goes for the whole equation, since we didnt swap any thing from left to right side of the equation or vice versa we can use this sign, to obtain the required inequality

$\mathsf{5y + 7.5 > 3x}$

dividing this inequality by 5, since there's no co-efficient in front of y in the given answers

we get

y + 1.5 > 0.6x

taking 1.5 to the RHS

that is the last option

5 0

3 years ago

How do I solve this?

iren2701 [21]

First you collect the like term then variable one side coefficient one side and constant

8 0

3 years ago

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