The actual number is 151.34 but since its a estimate about 150ish
Answer:
d≤48/2.15
Step-by-step explanation:
Step one:
Given data
Claudia spends $2.15 a day for lunch.
We are told that her balance is $48.00
let the number of days be d
Step two:
The maximum number of days she can eat is given as
d≤48/2.15
d≤22.33 days
Answer:
<em>least</em><em> </em><em>to</em><em> </em><em>greatest</em>
<em>.</em><em>86</em><em>,</em><em> </em><em>8</em><em>/</em><em>9</em><em>,</em><em> </em><em>.</em><em>9</em>
Answer:
1. D. 20, 30, and 50
2. A. 86
3. B. 94
Step-by-step explanation:
1. To find the outliers of the data set, we need to determine the Q1, Q3, and IQR.
The Q1 is the middle data in the lower part (first 10 data values) of the data set (while the Q3 is the middle data of the upper part (the last 10 data values) the data set.
Since it is an even data set, therefore, we would look for the average of the 2 middle values in each half of the data set.
Thus:
Q1 = (85 + 87)/2 = 86
Q3 = (93 + 95)/2 = 94
IQR = Q3 - Q1 = 94 - 86
IQR = 8
Outliers in the data set are data values below the lower limit or above the upper limit.
Let's find the lower and upper limit.
Lower limit = Q1 - 1.5(IQR) = 86 - 1.5(8) = 74
The data values below the lower limit (74) are 20, 30, and 50
Let's see if we have any data value above the upper limit.
Upper limit = Q3 + 1.5(IQR) = 94 + 1.5(8) = 106
No data value is above 106.
Therefore, the only outliers of the data set are:
D. 20, 30, and 50
2. See explanation on how to we found the Q1 of the given data set as explained earlier in question 1 above.
Thus:
Q1 = (85 + 87)/2 = 86
3. Q3 = (93 + 95)/2 = 94
Answer:
Frank
Step-by-step explanation:
First let's start by calculating the speed of each runner.
Let's use feet per second
Frank's speed is already given in feet per second: 14 feet/second
We are given that Jake runs 382 feet in 38 seconds. To bring this down to feet/second we need to divide both numbers by 38.
382/38=10.05 feet/second (about)
We are given that Will runs 1 mile in 394 seconds. 1 mile is equivalent to 5280 feet. Now we divide both numbers by 394 to bring it down to feet/second.
5280/394=13.401 feet/second (about)
We are given that Ron runs 555 feet in 1 minute. 1 minute is equivalent to 60 seconds. Now we divide both numbers by 60 to bring it down to feet/second.
555/60=9.25 feet/second
After comparing all the speeds, we can conclude that Frank runs the fastest
