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USPshnik [31]
3 years ago
6

Charlotte reads 8 1/3 pages of a book in 10 minutes. What is her average reading rate in pages per minute?

Mathematics
1 answer:
sukhopar [10]3 years ago
8 0
8\frac{1}{3} = \frac{25}{3}

25/3 pages of a book in 10 minutes

Multiply both numbers by the reciprocal of 10, which is 1/10

\frac{25}{3} \times\frac{1}{10} = \frac{25}{30}=\frac{5}{6}

10\times\frac{1}{10}= 1

So, Charlotte reads 5/6 pages of a book in 1 minute.
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What is the value of x in the equation 4x+8y=40 when y = 0.8
fgiga [73]

When y=0.8

4x +8(0.8) =40

-> 4x +6.4 =40

-> 4x = 33.4

-> x=33.4/4

-> x=8.35

Hope it helps...

Regards;

Leukonov/Olegion.

8 0
3 years ago
A regression equation that predicts the price of homes in thousands of dollars is t = 24.6 + 0.055x1 - 3.6x2, where x2 is a dumm
AveGali [126]

Answer:

a) On average, homes that are on busy streets are worth $3600 less than homes that are not on busy streets.

Step-by-step explanation:

For the same home (x1 is the same), x2 = 1 if it is on a busy street and x2 = 0 if it is not on a busy street. If x2 = 1, the value of 't' decreases by 3.6 when compared to the value of 't' for x2=0. Since 't' is given in thousands of dollars, when a home is on a busy street, its value decreases by 3.6 thousand dollars.

t(x1, 0)= 24.6 + 0.055x1\\t(x1, 1) = 24.6 + 0.055x1 - 3.6\\t(x1, 1) = t(x1, 0) - 3.6

Therefore, the answer is a) On average, homes that are on busy streets are worth $3600 less than homes that are not on busy streets.

8 0
3 years ago
Eden just bought a trough in the shape of a rectangular prism for her horses. She needs to know what volume of water to add to t
notsponge [240]

The volume of the trough is V(w) = w³ + 20w² - 429w and the rate of change of the volume over a width of 38 inches to 53 inches is 4695 in³/in

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more variables and numbers.

Let w represent the width, hence:

length = w + 33, height = w - 13

Volume (V) = w(w + 33)(w - 13) = w³ + 20w² - 429w

V(w) = w³ + 20w² - 429w

Rate of change = dV/dw = 3w² + 40w - 429

When w = 38, dV/dw = 3(38)² + 40(38) - 429 = 5423

When w = 53, dV/dw = 3(53)² + 40(53) - 429 = 10118

Rate = 10118 - 5423 = 4695 in³/in

The volume of the trough is V(w) = w³ + 20w² - 429w and the rate of change of the volume over a width of 38 inches to 53 inches is 4695 in³/in

Find out more on equation at: brainly.com/question/2972832

#SPJ1

4 0
1 year ago
How to sketch the solutions to each. systems of inequalities
zloy xaker [14]
It depends what inequality you have
4 0
3 years ago
What is the constant term that completes the perfect square trinomial. y^2 + y
lara [203]
Y^2 + y

y^2 + y + 0.25 <=== the constant term is 0.25
(y + 0.5)(y + 0.5) =
(y + 0.5)^2

to find the constant, u take half of ur y coefficient (not the y^2 coefficient)....y^2 + 1y....ur y coefficient is 1......half of it is 0.5....u then square it....(0.5^2) = 0.25 ....this is ur constant
4 0
3 years ago
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