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igomit [66]
3 years ago
11

The ymca lap pool is a right rectangular prism 36.8\, \text{m}36.8m36, point, 8, space, m long by 20 \,\text{m}20m20, space, m w

ide. the pool contains 1472 \text{ m}^31472 m 3 1472, space, m, start superscript, 3, end superscript of water. how deep is the water in the pool?
Mathematics
2 answers:
Jlenok [28]3 years ago
7 0
The volume of a rectangular prism is given by:
 V = (w) * (l) * (h)
 Where,
 w: width
 l: length
 h: height
 Substituting values we have:
 1472 = (20) * (36.8) * (h)
 Clearing h we have:
 h = (1472) / ((20) * (36.8))
 h = 2 m
 Answer:
 
the water in the pool is 2m deep
erastovalidia [21]3 years ago
4 0

Answer:

2 m deep

Step-by-step explanation:

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Elenna [48]
Part A
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The x-intercept is (-2,0). 

To solve for the y-intercept, we set x=0. That is 
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The y-intercept is (0, 8) 

The coordinates of the optimum point are actually the vertex which can be easily seen from the vertex form equation given above. The minimum point is (-3, -1).

Part B.
We have g\left(x\right)=-2x^2+8x+3.
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Part C
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4 0
4 years ago
Can you tell me if a Quadra lateral has for obtuse angles
Sphinxa [80]
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5 0
3 years ago
In the equation below, for what value of c does x = 4?<br> 1 / (2x + 4) = 3x-c
rodikova [14]

Answer:

Option D.

Jenn's answer is not correct. She got it substituting c=4 into the equation and solving for "x".

Step-by-step explanation:

Given the following equation:

\frac{1}{2}(2x + 4) = 3x-c

Since you need that x=4, you hace to substitute that value into the equation:

\frac{1}{2}(2(4) + 4) = 3(4)-c

Now you need to solve for "c":

\frac{1}{2}(8 + 4) = 12-c\\\\\frac{12}{2}= 12-c\\\\6=12-c\\\\c+6=12\\\\c=12-6\\\\c=6

Therefore for a  a value of c=6, you get x=4

Then, the you can identify that the correct answer is the one given in the Option D.

Jenn made a mistake, because she substituted c=4 into the equation and then solve for "x":

\frac{1}{2}(2x + 4) = 3x-(4)\\\\x+2=3x-4\\\\2+4=3x-x\\\\6=2x\\\\\frac{6}{2}=x\\\\x=3

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Step-by-step explanation:

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